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-BARSIC- [3]
2 years ago
13

Blank measurements are useful for determining buoyancy and identifying relationships between substances.

Chemistry
1 answer:
ozzi2 years ago
5 0
I choose the letter c witch is density I believe that it’s useful for determining identifying relationships between substances
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Consider the following reaction:
lesya692 [45]

Answer:

A

Explanation:

I think it's the answer

6 0
2 years ago
Which statement best describes the behavior of most soilds?
lidiya [134]
B is correct. Molecules move faster when they are hotter because they have more energy. You can notice this change with your naked eye. Molecules in solids don't move. They have barely any energy. Hope this helps! ;)
6 0
3 years ago
Read 2 more answers
A group of birds eat fruit from a tree. The fruit falls to the ground where
olchik [2.2K]

Answer:

Both answer choice 2 and answer choice 3 are correct choices.

Explanation:

Biotic factors are living components in an ecosystem. They are living organisms which affect another living component in an ecosystem.

Antibiotic factors are non living components of an ecosystem. They are chemicals which affect living organisms.

The choice 2 is correct. The seeds spread out by mice is a biotic factor interacting with an antibiotic factor

Choice 3 is correct. The seeds in the soil grow into new trees are biotic factors interacting with an antibiotic factor

3 0
3 years ago
Which one of these are correct?
Sergio [31]

The correct answer is the one in the middle. Mixing food coloring and water

3 0
3 years ago
A certain metal M forms a soluble sulfate salt MSO, Suppose the left half cell of a galvanic cell apparatus is filled with a 3.0
bija089 [108]

Answer:

E = 0.062 V

Explanation:

(a) See the attached file for the answer

(b)

Calculating the voltage (E) using the formula;

E = - (2.303RT/nf)log Cathode/Anode

Where,

R = 8.314 J/K/mol

T = 35°C = 308 K

F- Faraday's constant = 96500 C/mol,

n = number of moles of electron = 2

Substituting, we have

E = -(2.303 * 8.314 *308/2*96500) *log (0.03/3)

   = -0.031 * -2

  = 0.062V

Therefore, the voltmeter will show a voltage of 0.062 V

5 0
2 years ago
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