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adell [148]
2 years ago
14

Addition of 12 M (concentrated) HCl to saturated NaCl results in precipitation of NaCl. Yet when 1 M HCl is added to the same Na

Cl solution, no precipitate forms. Explain.
Chemistry
1 answer:
Marina86 [1]2 years ago
6 0

Answer:

When we add 12M HCl, reaction quotient Qsp becomes greater than Ksp of NaCl leading to precipitation

Explanation:

When sodium chloride is dissolved in water, the equilibrium dissolution process known as Ksp is set up as typified by the equation;

NaCl(s)------> Na^+(aq) + Cl^-(aq)

According to Le Chatelier's principle, this system will remain in equilibrium after the addition of the 1M HCl. This explains why there will not be any change in the system after adding this solution.

However, addition of 12 M HCl will significantly distort the equilibrium position since there is now more Cl^- ion in the system. The system now seeks to relieve this stress by recrystallizing more sodium chloride leading to the formation of a precipitate. Succinctly put, when we add the 12M HCl, the reaction quotient Qsp becomes greater than Ksp of NaCl leading to precipitation of NaCl crystals.

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3 years ago
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A sample of helium gas occupies a volume of 152.0 mL at a pressure of 717.0 mm Hg and a temperature of 315.0 K. What will the vo
kozerog [31]

Answer:

0.581 L  or  581 mL

Explanation:

As stated in the question, the combined gas law is (P1*V1/T1) = (P2*V2/T2)

Write down the amounts you are given.

V1 = 0.152 L (I was taught to always convert milliliters to liters)

P1 = 717 mmHg

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V2 = ?

P2 = 463 mmHg

T2 = 777 K

The variable that is being solved for is final volume. Fill in the combined gas law equation with the corresponding amounts and solve for V2.

(717 mmHg*0.152 L) / (315 K) = (463 mmHg*V2) / (777 K)

0.346 = (463*V2) / (777)

0.346*777 = (463*V2) / (777)*777

268.842 = 463*V2

268.842/463 = (463*V2)/463

V2 = 0.581

Pressure and volume are indirectly proportional. This checks out because the volume increased while pressure decreased. Volume and temperature are directly proportional. This checks out because both volume and temperature increased. This is a good way to check your answers. You can also solve each side of the combined gas law equation to see if they are both the same.

6 0
2 years ago
If 88.0 L of natural gas, which is essentially methane (CH4), undergoes complete combustion at 720. mm Hg and 22ºC, how many gra
mr_godi [17]

126 grams of H2O is formed.

Explanation:

Data given:

volume of the gas = 88 Liters

pressure = 720 mm Hg or 0.947 atm

temperature T = 22 Degrees or 295.15 K

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n =?

The formula is used is of ideal gas law to know the number of moles of CH4 undergoing combustion.

PV = nRT

n = \frac{PV}{RT}

putting the values in the equation

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1 mole of CH4 undergoes combustion to form 2 moles of water

3.5 moles will give x moles of water

2/1 = x/3.5

x =  7 moles of water  (atomic mass of water = 18 gram/mole)

mass = atomic mass x number of moles

mass = 18 x 7

          =126 grams of water is formed.

7 0
3 years ago
Electron configuration for Be2+
rusak2 [61]

Answer:

Beryllium has an electronic configuration of 1s2 2s2 in its natural state. When in an ion state of Be2+ it loses the electrons in a 2s shell and has a configuration of 1s2. This means that Be2+ has 2 electrons.

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