Answer:
X(Cl-35) = 75.95% => Answer 'A'
Explanation:
34.9689·X(Cl-35) + 36.9695·X(Cl-37) = 35.45; X = fractional abundance
X(Cl-35) + X(Cl-37) = 1 ⇒ X(Cl-37) = 1 - X(Cl-25)
34.9689·X(Cl-35) + 36.9695(1 - X(Cl-35)) = 35.45
34.9689·X(Cl-35) + 36.9695 - 36.9695·X(Cl-35) = 35.45
Rearrange ...
36.9695·X(Cl-35) - 34.9689·X(Cl-35) = 36.9689 - 35.45
2.0006·X(Cl-35) = 1.5195
X(Cl-35) = 1.5195/2.0006 = 0.7595 fractional abundance
⇒ % abundance = 75.95%
Answer:
Explanation:
38736 ÷ 4784 = 8.097
Sig Figs
4
8.097
Decimals
3
8.097
Scientific Notation
8.097 × 10^0
E-Notation
8.097e+0
Words
eight point zero nine seven
For the given 200 g of 95% ethanol solution, ethanol is 190g and water is 10g. We determine the number of moles per component.
ethanol: (190 g ethanol) / (46 g/mole) = 4.13 moles
water: (10 g water)/(18 g/mole) = 0.55 moles
Total moles of the solution is 4.68 moles
Mole fraction of water: = 0.55 moles/4.68 moles = 0.117
I think it's a Oxygen Difluoride