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tresset_1 [31]
3 years ago
6

NEED ANSWER ASAP

Chemistry
1 answer:
Solnce55 [7]3 years ago
8 0
The phase change is called deposition, when a gas transforms into a solid without passing through the liquid phase.
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what is the change in the velocity of the biker below as he travels from point b to point c ? ..... What is his acceleration fro
Furkat [3]

The change in the velocity = 4 m/s

Acceleration = 4 m/s²

<h3>Further explanation</h3>

Given

vo = initial velocity = 4 m/s

vf = final velocity = 8 m/s

t = 1 s

Required

The change in the velocity

Acceleration

Solution

the change in velocity =

\tt vf-vo=8-4=4~m/s

Acceleration = ratio of a change in velocity and the time

\tt a=\dfrac{\Delta v}{t}= \dfrac{vf-vo}{t}

Input the value :

\tt a=\dfrac{4~m/s}{1~s}=4~m/s^2

7 0
3 years ago
30cm^3 of a dilute solution of Ca(OH)2 required 11 cm^3 of 0.06 mol/dm^. Hcl for complete neutralization. Calculate the concentr
Alenkasestr [34]

Answer: Thus concentration of Ca(OH)_2 in mol/dm^3  is 0.011 and in g/dm^3 is 0.814

Explanation:

To calculate the concentration of Ca(OH)_2, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Ca(OH)_2

We are given:

n_1=1\\M_1=0.06mol/dm^3\\V_1=11cm^3=0.011dm^3\\n_2=2\\M_2=?\\V_2=30cm^3=0.030dm^3         1cm^3=0.001dm^3

Putting values in above equation, we get:

1\times 0.06mol/dm^3\times 0.011dm^3=2\times M_2\times 0.030dm^3\\\\M_2=0.011mol/dm^3

The concentration in g/dm^3 is 0.011mol/dm^3\times 74g/mol=0.814g/dm^3

Thus concentration of Ca(OH)_2 is 0.011mol/dm^3 and 0.814g/dm^3

4 0
3 years ago
Three different atoms or atomic cations with 3 electrons.
sveticcg [70]

Answer:

Li, Be^+, B^{2+}

Explanation:

To answer this question successfully, we need to remember that atoms are neutral species, since the number of protons, the positively charged particles, is equal to the number of electrons, the negatively charged particles. That said, we may firstly find an atom which has 3 electrons (and, as a result, 3 protons, as it should be neutral).

The number of protons is equal to the atomic number of an element. We firstly may have an atom with 3 protons and 3 electrons (atomic number of 3, this is Li).

Similarly, we may take the atomic number of 4, beryllium, and remove 1 electron from it. Upon removing an electron, it would become beryllium cation, Be^+.

We may use the same logic going forward and taking the atomic number of 5. This is boron. In this case, we need to remove 2 electrons to have a total of 3 electrons. Removal of 2 electrons would yield a +2-charged cation: B^{2+}.

6 0
3 years ago
What is the volume of a sample of ammonia gas (NH3) if it contains 0.23 moles?​
LekaFEV [45]

The volume of a sample of ammonia gas : 5.152 L

<h3>Further explanation</h3>

Given

0.23 moles of ammonia

Required

The volume of a sample

Solution

Assumed on STP

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.

So for 0.23 moles :

= 0.23 x 22.4 L

= 5.152 L

8 0
2 years ago
How many kilograms of solvent (water) must 0.71 moles of KI be dissolved in to produce a 1.93 m solution?
GalinKa [24]

Answer: kg= 0.37

Explanation:

Use the molality formula.

M= m/kg

6 0
3 years ago
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