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qaws [65]
2 years ago
11

Helpppp!!!!!!!<( ̄︶ ̄)>​

Chemistry
2 answers:
Firlakuza [10]2 years ago
8 0

Answer:

<h2><em>Boiling</em></h2>

Explanation:

The condition of free vaporization throughout the liquid is called <em><u>B</u></em><em><u>oil</u></em><em><u>ing</u></em><em><u>.</u></em>

The Boiling Temperature is the temperature at which the vapour pressure of liquid is equal to external pressure.

kipiarov [429]2 years ago
6 0

The condition of free vaporisation throughout the liquid is called

  • <em>(</em><em>4</em><em>)</em><em> </em><em>Boiling</em><em> </em>

<u>We</u><u> </u><u>can</u><u> </u><u>also</u><u> </u><u>define</u><u> </u><u>it</u><u> </u><u>as</u><u> </u><u>Free</u><u> </u><u>vaporisation</u><u> </u><u>throughout</u><u> </u><u>the</u><u> </u><u>liquid</u><u> </u><u>is</u><u> </u><u>called</u><u> </u><u>boiling</u><u>,</u><u> </u><u>basically</u><u> </u><u>its</u><u> </u><u>the</u><u> </u><u>definition</u><u> </u><u>of</u><u> </u><u>boiling</u><u>.</u><u> </u>

<u>*</u><u>Note</u><u> </u><u>that</u><u>:</u><u>-</u><u> </u><u>The</u><u> </u><u>temperature</u><u> </u><u>at</u><u> </u><u>which</u><u> </u><u>vapour</u><u> </u><u>pressure</u><u> </u><u>of</u><u> </u><u>liquid</u><u> </u><u>is</u><u> </u><u>equal</u><u> </u><u>to</u><u> </u><u>external</u><u> </u><u>pressure</u><u> </u><u>is</u><u> </u><u>called</u><u> </u><u>Boiling</u><u> </u><u>temperature</u><u>.</u><u>.</u>

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Calculate the percent composition by mass of the following compounds that are important starting materials for synthetic polymer
notsponge [240]

Answer:

C₃H₄O₂ → 50% C; 5.5 % H; 44.5% O

C₄H₆O₂ → 56 % of C; 7 % of H; 37% of O

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Explanation:

We determine the molar mass of each compound:

C₃H₄O₂ → 72 g/mol

In 1 mol of acrylic acid (72 g), we have:

3 moles of C → 12 g/mol . 3 mol = 36 g of C

4 moles of H → 1 g/mol . 4 mol = 4 g of H

2 moles of O → 16g/mol . 2 mol = 32 g of O

Then in 100 g of salt, we may have:

100 . 36 / 72 = 50 % of C

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C₄H₆O₂ → 86 g/mol

In 1 mol of methyl acrylate (86 g), we have:

4 moles of C → 12 g/mol . 4 mol = 48 g of C

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100 . 48 / 86 = 56 % of C

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C₃H₃N → 53 g/mol

In 1 mol of acrylonitrile (53 g), we have:

3 moles of C → 12 g/mol . 3 mol = 36 g of C

3 moles of H → 1 g/mol . 3 mol = 3 g of H

1 mol of N → 14g/mol . 1 mol = 14 g of N

Then in 100 g of salt, we may have:

100 . 36 / 53 = 68 % of C

3 . 100 / 53 = 6 % of H

14 . 100 / 53 = 26 % of N

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