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2 years ago

Please help me thank youi have 2MINUTES LEFTT

Mathematics

1 answer:

ehidna [41]2 years ago

6 0

Answer:

55°

Step-by-step explanation:

2 is congruent with 1

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HELP!!!!!

schepotkina [342]

Answer:

The correct answer option is B.

Step-by-step explanation:

We are given a graph with different intervals A, B, C and D and we are to figure out whether which of these intervals on the graph can be describes as linear increasing.

From the given interval options, we can see that C is constant while the intervals A and D are decreasing linear.

Its the interval B which can be describes as linear increasing since it has a positive slope.

3 0

3 years ago

Read 2 more answers

I really need help plzzzzz

Marianna [84]

Answer:

All similar, see below

Step-by-step explanation:

Angles

26° & 64° & 90°
AA similarity

Ratios of corresponding sides:

6/8 = 9/12 = 12/16 ⇒ 3/4
SSS similarity

Angle C is vertical

∠ACB ≅ ∠DCE

Ratios of corresponding sides:

9/15 = 18/30 ⇒ 3/5
SAS similarity

6 0

2 years ago

The sales of a grocery store had an average of $8,000 per day. The store introduced several advertising campaigns in order to in

oksano4ka [1.4K]

Answer:

Null hypothesis: $\mu \leq 8000$

Alternative hypothesis: $\mu > 8000$

$z=\frac{8300-8000}{\frac{1200}{\sqrt{64}}}=2$

$p_v =P(Z>2)=0.0228$

Step-by-step explanation:

1) Data given and notation

$\bar X=8300$ represent the sample mean

$\sigma=1200$ represent the population standard deviation

$n=64$ sample size

$\mu_o =800$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

2) State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 8000, the system of hypothesis are :

Null hypothesis: $\mu \leq 8000$

Alternative hypothesis: $\mu > 8000$

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

3) Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{8300-8000}{\frac{1200}{\sqrt{64}}}=2$

4) P-value

Since is a one-side upper test the p value would given by:

$p_v =P(Z>2)=0.0228$

5) Conclusion

If we compare the p value and the significance level assumed, for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is significantly higher than $8000.