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hodyreva [135]
2 years ago
14

I need help with this is this circumference or areas will mark you brainly if right

Mathematics
1 answer:
Pani-rosa [81]2 years ago
6 0
The question is cut off, but here are the formulas for area and circumference:

A = pi * r^2
C = 2 * pi * r
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Convert to standard form: y=1/3x + 3/4
ira [324]

Answer:

4x-12y=9

Step-by-step explanation:

y=1/3 x + 3/4

1/3 x-y=3/4

(x-3y)/3=3/4

4(x-3y)=3×3

4x-12y=9

6 0
2 years ago
How many different breakfasts can you have at the local diner if you can select 3 different egg dishes​ (scrambled, fried,​ poac
faltersainse [42]

To find the total number of combinations, multiply all the choices together:

3 eggs x 4 meats x 5 breads x 6 juices x 4 beverages:

3 x 4 x 5 x 6 x 4 = 1,440 different breakfasts

6 0
3 years ago
Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.
likoan [24]

Answer:

Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

Step-by-step explanation:

Consider, the given Quadratic equation, x^2+4=6x

This can be written as ,  x^2-6x+4=0

We have to solve using quadratic formula,

For a given quadratic equation ax^2+bx+c=0 we can find roots using,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}  ...........(1)

Where,  \sqrt{b^2-4ac} is the discriminant.

Here, a = 1 , b = -6 , c = 4

Substitute in (1) , we get,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

\Rightarrow x=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot 1 \cdot (4)}}{2 \cdot 1}

\Rightarrow x=\frac{6\pm\sqrt{20}}{2}

\Rightarrow x=\frac{6\pm 2\sqrt{5}}{2}

\Rightarrow x={3\pm \sqrt{5}}

\Rightarrow x_1={3+\sqrt{5}} and \Rightarrow x_2={3-\sqrt{5}}

We know \sqrt{5}=2.23607(approx)

Substitute, we get,

\Rightarrow x_1={3+2.23607}(approx) and \Rightarrow x_2={3-2.23607}(approx)

\Rightarrow x_1={5.23607}(approx) and \Rightarrow x_2=0.76393}(approx)

Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

7 0
2 years ago
Read 2 more answers
The sides of a triangle are 1, x, and x2. what are possible values of x?
Whitepunk [10]
The sides of the triangle are given as 1, x, and x².

The principle of triangle inequality requires that the sum of the lengths of any two sides should be equal to, or greater than the third side.

Consider 3 cases
Case (a):  x < 1,
      Then in decreasing size, the lengths are 1, x, and x².
      We require that x² + x ≥ 1
      Solve x² + x - 1 = 
      x = 0.5[-1 +/- √(1+4)] = 0.618 or -1.618.
      Reject the negative length.
     Therefore, the lengths are 0.382, 0.618 and 1.

Case (b): x = 1
   This creates an equilateral triangle with equal sides
    The sides are 1, 1 and 1.

Case (c): x>1
  In increasing order, the lengths are 1, x, and x².
  We require that x + 1 ≥ x²
  Solve x² - x - 1 = 0
  x = 0.5[1 +/- √(1+4)] = 1.6118 or -0.618
  Reject the negative answr.
 The lengths are 1, 1.618 and 2.618.

Answer:
The possible lengths of the sides are
(a) 0.382, 0.618 and 1
(b) 1, 1 and 1.
(c) 2.618, 1.618 and 1.

7 0
3 years ago
Use models to show the sum of 120+205
maksim [4K]

Answer:

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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