Answer:
Explanation:
1 mile=5280 ft
1 hour=3600 seconds
Changing speed from mi/h to ft/s

Time of flight, 
From fundamental kinematics equations
where g is acceleration due to gravity whose value is taken as 32.2 ft/s2 and h is the distance
By substitution

Answer:
α = 1.875 rad/s²
t = 8 s
Explanation:
α = ω²/2θ = 15²/(2(60)) = 1.875 rad/s²
t = ω/a = 15 / 1.875 = 8 s
Answer:
Conservation of Energy: the total energy of the system is constant. Conservation of Momentum: the mass times the velocity of the center of mass is constant. Conservation of Angular Momentum: The total angular momentum of the system is constant.
Explanation:
none
Answer:
(a) 
(b)
: From the air to the surroundings.
Explanation:
Hello,
(a) In this case, we can compute the area at the entrance by firstly computing the inlet volumetric flow:

Then, with the velocity, we compute the area:

(b) In this case, via the following energy balance for the nozzle:

We can easily compute the change in the enthalpy by using the given Cp and neglecting the work (no done work):

Finally, the heat turns out:
![Q=-348.795kW+\frac{1}{2}*2.3\frac{kg}{s}*[(460\frac{m}{s})^2 -(3\frac{m}{s})^2 ]\\\\Q=-348.795kW+243329.65W*\frac{1kW}{1000W}\\ \\Q=-105.5kW](https://tex.z-dn.net/?f=Q%3D-348.795kW%2B%5Cfrac%7B1%7D%7B2%7D%2A2.3%5Cfrac%7Bkg%7D%7Bs%7D%2A%5B%28460%5Cfrac%7Bm%7D%7Bs%7D%29%5E2%20%20%20-%283%5Cfrac%7Bm%7D%7Bs%7D%29%5E2%20%20%5D%5C%5C%5C%5CQ%3D-348.795kW%2B243329.65W%2A%5Cfrac%7B1kW%7D%7B1000W%7D%5C%5C%20%5C%5CQ%3D-105.5kW)
Such sign, means the heat is being transferred from the air to the surroundings.
Regards.
Answer: 1.65
Explanation: Snell's law says that index of refraction of the first material times sine theta one equals index of refraction of the second material, which we don't know, multiplied by sine theta two, . So, we'll solve this for N two by dividing both sides by sine theta two. So, N two is N one sine theta one over sine theta two . So, that's 1.33 index of refraction of water times sine of 45.7degrees incidence angle divided by sine of 30.5 degrees angle of refraction, giving us 1.65.
The formula for snell's law is N1*sintheta1=N2*sinetheta2