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uysha [10]
3 years ago
5

Need help ASAP plz I have to finish but I’m stuck here

Mathematics
1 answer:
labwork [276]3 years ago
8 0
Ello I think it could be B
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A patient with end-stage kidney disease has nine family members who are potential kidney donors. How many possible orders are th
eduard

Answer: 504

Step-by-step explanation:

When we select r things from n things in a order , we use permutations.

Formula for permutation:  ^nP_r=\dfrac{n!}{(n-r)!}

Given : The number of family members who are potential kidney donors. = 9

Number of people needed to be selected for best match, a second-best match, and a third-best match ( in an order)=3

Then, the number of possible orders are = ^9P_3=\dfrac{9!}{(9-3)!}

=\dfrac{9\times8\times7\times6!}{6!}=504

Hence, the number of possible orders 504.

4 0
3 years ago
Let If f(x)=9 what is x
Eddi Din [679]

9/f would be your answer. Hope I helped

4 0
3 years ago
Read 2 more answers
Find the solution of the initial value problem<br><br> dy/dx=(-2x+y)^2-7 ,y(0)=0
Leokris [45]

Substitute v(x)=-2x+y(x), so that \dfrac{\mathrm dv}{\mathrm dx}=-2+\dfrac{\mathrm dy}{\mathrm dx}. Then the ODE is equivalent to

\dfrac{\mathrm dv}{\mathrm dx}+2=v^2-7

which is separable as

\dfrac{\mathrm dv}{v^2-9}=\mathrm dx

Split the left side into partial fractions,

\dfrac1{v^2-9}=\dfrac16\left(\dfrac1{v-3}-\dfrac1{v+3}\right)

so that integrating both sides is trivial and we get

\dfrac{\ln|v-3|-\ln|v+3|}6=x+C

\ln\left|\dfrac{v-3}{v+3}\right|=6x+C

\dfrac{v-3}{v+3}=Ce^{6x}

\dfrac{v+3-6}{v+3}=1-\dfrac6{v+3}=Ce^{6x}

\dfrac6{v+3}=1-Ce^{6x}

v=\dfrac6{1-Ce^{6x}}-3

-2x+y=\dfrac6{1-Ce^{6x}}-3

y=2x+\dfrac6{1-Ce^{6x}}-3

Given the initial condition y(0)=0, we find

0=\dfrac6{1-C}-3\implies C=-1

so that the ODE has the particular solution,

\boxed{y=2x+\dfrac6{1+e^{6x}}-3}

5 0
3 years ago
40% of what number is 82?
Naya [18.7K]
82*100/40 = 205 

<span>40% 0f 205 = 205*40% = 205*40/100 = 82
hopes this helps :) :D :)</span>
4 0
3 years ago
Read 2 more answers
Blhvjh gjfgfkytdkykdyrckhg
Dimas [21]

Answer:

tvubhgfyvug fyicvuui

Step-by-step explanation:

blhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhg

8 0
3 years ago
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