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andrew-mc [135]
3 years ago
11

X-4y=-12 and 5x=20y+60 How do you solve this

Mathematics
2 answers:
Savatey [412]3 years ago
6 0
Here is the answers.

Nookie1986 [14]3 years ago
6 0

Answer:

You must turn the variables, or the "x" into a number to make the numbers on the left equal the numbers on the right.

Step-by-step explanation:

In order to solve these problems, you must replace the variable with a number to have the equation on the left equal what is on the right.

Equation 1:

x - 4y = -12 <----- This is the original problem.

-8 - 4y = -12 <----- Replace the variable.

-12y = -12 <----- This is a true statement.

Equation 2:

  5x=20y+60 <----- This is the original problem.

5(16) =20y+60 <----- Replace the variable/Do the addition.

80 = 80y <------ This is a true statement.

Hope this helps! :D

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How do you preform the indicated operation <br> 14 - (-10) ?
Gemiola [76]

Answer:

\Huge \boxed{24}

Step-by-step explanation:

To solve this problem, first you have to apply the rule of adding numbers from left to right.

\displaystyle -(-c)=c

\displaystyle 14+10

Then, add numbers from left to right.

\displaystyle 14+10=24

As a result, the correct is 24.

<h2>Hope this helps!</h2><h2 /><h2>Have a wonderful blessing day! :)</h2><h2 /><h2>Good luck! :)</h2>
7 0
3 years ago
Write an equation in standard form for the line that passes through (4, 4) and has a x-intercept of 3?
Nikolay [14]

Answer:

y=4(x-3)

Step-by-step explanation:

if x=3, subtract 3 from each side to get x-3=0

point (4, 4). That is, when x=4, y=4.

Plug those in and solve for a.  

y=a(x-3)

4=a(4-3)

4=a(1)

4=a

 Thus,  

y=4(x-3)

8 0
3 years ago
Draw the largest possible square inside an equilateral triangle, with one side of the square aligned with one side of the triang
Ronch [10]

Answer:

Rectangular area

side a  =  3 units

side b  = 2.60 units

Step-by-step explanation: See annex

We have an equilateral triangle (3 equal sides, three equal inside angles)

side length  =  6

∠  ABC  = ∠BCA  = ∠CAB  =  60⁰  

tan 60⁰  =  sin 60⁰/cos 60⁰    =  √3/2 / 1/2    

tan 60⁰  = √3    

From annex

tan ∠ ABC    =   √3   =  b/x      then    b  =  √3 * x

and   a  =  6 - 2*x     ( by symmetry)

Then

A = a*b

A(x)  =  ( 6 - 2*x ) * √3 *x

A(x)  =  6*√3 *x - 2*√3 *x²

Taking derivatives on both sides of the equation we get:

A´(x)  =  6*√3  - 4*√3 *x    ⇒    A´(x)  = 0      ⇒  6*√3  - 4*√3 *x  = 0

x =  6/4         ⇒     x   =  1.5

then    a  =  6 - 2*x         ⇒    a  =  6 - 3   ⇒     a  =  3 (units)

and  b  =  √3*x   =  1.5 *√3  =  2.60 units

We get a rectangle (almost a square)

7 0
3 years ago
NEED HELP ASAP
elena-14-01-66 [18.8K]
Ans A 

<span>look at the graph for x = 2.... </span>
<span>2^4 = 16 ..and the graph looks like it approx = 8 for x=2 </span>
<span>this suggests (1/2)x^4 </span>
<span>you can eliminate answers C and D straight off because the graph is never negative</span>
4 0
3 years ago
Help with this question!Please
Sedbober [7]

Answer:

x = 14 for the first one, x = 60 for the second one

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
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