This is the concept of algebra, to solve the expression we proceed as follows;
cos 2x-cosx=0
cos 2x=cosx
but:
cos 2x+1=2(cos^2x)
thereore;
from:
cos 2x=cos x
adding 1 on both sides we get:
cos 2x+1=cos x+1
2(cos^2x)=cosx+1
suppose;
cos x=a
thus;
2a^2=a+1
a^2-1/2a-1/2=0
solving the above quadratic we get:
a=-0.5 and a=1
when a=-0.5
cosx=-0.5
x=120=2/3π
when x=1
cos x=1
x=0
the answer is:
x=0 or x=2/3π
Answer:
Simplified: -2x + 2
x multiplied by 7: -14x + 2
Step-by-step explanation:
5x + 3 - 7x - 1
= -2x + 2
-2x ( 7 ) + 2
= -14x + 2
Answer:
BC = 25
Step-by-step explanation:
If the base angles are equal, then the sides opposite them are as well.
- 4x + 4 = 6x - 14 Subtract 4x from both sides
- 4x - 4x + 4 = 6x - 4x - 14 Combine
- 4 = 2x - 14 Add 14 to both sides
- 4 + 14 = 2x - 14 + 14 Combine
- 18 = 2x Divide by 2 and switch
- 2x/2 = 18/2 Combine
- x = 9
But that's not what you are asked for. You want the value of 2x + 7
- BC = 2x + 7
- BC = 2*9 + 7
- BC = 25
If there are no further records known of the sides measures then
AY is half WX
Yes, because both triangles are divisible by a certain number to equal to each side of each triangle.