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2 years ago

11

Mr nealy has $107.40 he withdrew $120 from the ATM. Does he have enough money to pay for the meal? If he has enough money, how m

uch change will he get back?

1 answer:

guapka [62]2 years ago

7 0

Answer: He has enough

Step-by-step explanation:120-107.40=12.60

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The base of 40-foot ladder is 8 feet from the wall. How high is the ladder on the wall (round to the nearest foot)

Nina [5.8K]

Given:

The base of 40-foot ladder is 8 feet from the wall.

To find:

How high is the ladder on the wall (round to the nearest foot).

Solution:

Ladder makes a right angle triangle with wall and ground.

We have,

Length of ladder (hypotenuse)= 40 foot

Base = 8 foot

We need to find the perpendicular to get the height of the ladder on the wall.

Let h be the height of the ladder on the wall.

According to the Pythagoras theorem,

$Hypotenuse^2=Base^2+Perpendicular^2$

$(40)^2=(8)^2+(h)^2$

$1600=64+h^2$

$1600-64=h^2$

$1536=h^2$

Taking square root on both sides.

$\pm \sqrt{1536}=h$

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Height cannot be negative. Round to the nearest foot.

$h\approx 39$

Therefore, the height of the ladder on the wall is 39 foot.

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3 years ago

The temperature went from -12°F to 18°F. How much did the temperature change

vlada-n [284]

Answer:

18 - (-12)

Step-by-step explanation:

Final temp. - Initial temp. = the change in temperature

By -12, we're indicating that is below zero (which is obvious) meaning that it is not in the "normal" scale nor in the imaginary scale of numbers. So, we can operate the following...

18 - (-12) = 30

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2 years ago

Use the net as an aid to compute the surface area (rounded to the nearest integer) of the triangular pyramid with an equilateral

aleksandrvk [35]

Answer:

Correct answer is $C)\ 254\ m^{2}$

Step-by-step explanation:

As per the given diagram, we know the following details:

Height of the triangular pyramid is <em>14m</em>.

<em>Side of base</em> = <em>10m </em>

Height of Triangular base = <em>8.7m</em>

Formula for <em>surface area of triangular pyramid</em>:

$\text{Area = Area of Triangular base + 3 }\times\text{Area of side triangle}$

(Triangular base is shown in the dotted lines in the question figure.

The other 3 triangles are the side triangles.)

We know that,

$\text{Area of a triangle = }\dfrac{1}{2} \times \text{Base} \times \text{Height}$

$\Rightarrow \text{Required Surface Area = } \dfrac{1}{2} \times 8.7 \times 10 + 3 \times \dfrac{1}{2} \times 14 \times 10\\\Rightarrow \dfrac{1}{2}\times (87 + 3 \times 140)\\\Rightarrow \dfrac{1}{2}\times (87 + 420)\\\Rightarrow \dfrac{1}{2} \times 507\\$\approx$ 254 m^{2}$

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Answer:

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