The volume is 12 mL (0.012 L)
Before the aluminum was added, the water reached 132mL. After it was added, it reached 144. That means the Aluminum takes up (144-132)= 12mL of space.
The density = mass/volume. If the aluminum bar has a mass of 78g and volume of 0.012L, 78/0.012=6,500 g/L
Answer:
-100.125
Explanation:
We are given
CH4 (g) + 2O2 (g) → CO2 (g) + 2H2O (l) △H = -890.0 kJ/mol
The given information is for complete reaction
we have 1.8grams of Methane
Molar mass of CH4 = 16
No of moles of Methane = 1.8/ 16
= 0.1125
So the amount of the heat will be released from the amount of the methane
Q = No of moles*( -890.0 kJ/mol)
= 0.1125*(-890)
= -100.125kJ/mole
Therefore the amount of Energy released from 1.8 grams of methane is equal to -100.125
Answer:
Strong acids are assumed 100% dissociated in water- True
As a solution becomes more basic, the pOH of the solution increases- false
The conjugate base of a weak acid is a strong base- true
The Ka equilibrium constant always refers to the reaction of an acid with water to produce the conjugate base of the acid and the hydronium ion- True
As the Kb value for a base increases, base strength increases- true
The weaker the acid, the stronger the conjugate base- true
Explanation:
An acid is regarded as a strong acid if it attains 100% or complete dissociation in water.
The pOH decreases as a solution becomes more basic (as OH^- concentration increases).
Ka refers to the dissociation of an acid HA into H3O^+ and A^-.
The greater the base dissociation constant, the greater the base strength.
The weaker an acid is, the stronger , its conjugate base will be.
Wrong, the electron configuration for antimony using the Nobel gas notation is: [Kr]5s24d105p3
<span>Metal + Polyatomic ion → ionic compound
I'm guessing ions since it is also an ionic compound</span>
