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kari74 [83]
3 years ago
14

The mass of an atomic number best refers to the number of

Chemistry
2 answers:
Vinvika [58]3 years ago
7 0
Answer:
Atomic number refers to the number of protons in an atom. It’s also used to identify what element it is, as every element has a different number of protons.
adelina 88 [10]3 years ago
5 0

Answer:

Mass number

Explanation:

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Gravity relates to a stream's ability to erode and deposit material by causing water to flow faster down a steep slope. True or
blsea [12.9K]

Answer:

true

Explanation:

4 0
3 years ago
When does raising the temperature of a gas increase its pressure?
GaryK [48]
A.) temperature

By raising the temperature the gas molecules speed up causing collisions with the volume of a container if kept constant.
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Sodium(na) is a highly reactive metal and chlorine is a poisonous gas. Which compound do they form when they chemically combine?
Nastasia [14]
It would form into NaCl because Na has a +1 charge while Cl has a -1 charge.
7 0
4 years ago
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At a certain temperature the equilibrium constant, Kc, equals 0.11 for the reaction:
Butoxors [25]

<u>Answer:</u> The equilibrium concentration of ICl is 0.27 M

<u>Explanation:</u>

We are given:

Initial moles of iodine gas = 0.45 moles

Initial moles of chlorine gas = 0.45 moles

Volume of the flask = 2.0 L

The molarity is calculated by using the equation:

\text{Molarity}=\frac{\text{Number of moles}}{\text{Volume}}

Initial concentration of iodine gas = \frac{0.45}{2}=0.225M

Initial concentration of chlorine gas = \frac{0.45}{2}=0.225M

For the given chemical equation:

2ICl(g)\rightarrow I_2(g)+Cl_2(g);K_c=0.11

As, the initial moles of iodine and chlorine are given. So, the reaction will proceed backwards.

The chemical equation becomes:

                      I_2(g)+Cl_2(g)\rightarrow 2ICl(g);K_c=\frac{1}{0.11}=9.091

<u>Initial:</u>         0.225      0.225

<u>At eqllm:</u>   0.225-x    0.225-x     2x

The expression of K_c for above equation follows:

K_c=\frac{[ICl]^2}{[Cl_2][I_2]}

Putting values in above equation, we get:

9.091=\frac{(2x)^2}{(0.225-x)\times (0.225-x)}\\\\x=0.135,0.668

Neglecting the value of x = 0.668 because equilibrium concentration cannot be greater than the initial concentration

So, equilibrium concentration of ICl = 2x = (2 × 0.135) = 0.27 M

Hence, the equilibrium concentration of ICl is 0.27 M

6 0
3 years ago
If Vanadium has an atomic number of 23 and an atomic mass of 50.9425u, how many neutrons are in one atom of Vanadium?
sergejj [24]
<h2>✏28 neutrons are in vanadium.</h2>

<h2 /><h2 /><h2 /><h2 /><h2>❤XxMrprathamxX13❤</h2>
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