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seropon [69]
3 years ago
7

100.mL of a .795 M solution of KBr is diluted to 500.mL. what is the new concentration of the solution?

Chemistry
1 answer:
kap26 [50]3 years ago
4 0

Answer:

0.159 M

Explanation:

convert from mL to L then use the equation:

M1V1 = M2V2

rearrange to find M2

\frac{M1V1}{V2} = M2

\frac{(0.795 M)(0.100 L)}{0.500 L} = 0.159 M

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A polar covalent bond is likely to form between 2 atoms that are C. Differ in electronegativity.
4 0
3 years ago
Report with correct significant figures in scientific notation <br>3.698 X 10^4÷1.85 X 10^2​
Alina [70]

Answer:

2.00x10^2

Explanation:

Hello!

In this case, we need to keep in mind that performing these types of operations require that the final result was shown with the same significant figures as the initial number with the fewest ones; it means, we show the final result with 3 significant figures, because 3.698 has four and 1.85 has three significant figures; therefore, we obtain:

3.698 x 10^4/1.85x10^2\\\\2.00x10^2

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5 0
3 years ago
You have a sample containing 2.39 moles of silver. How many atoms of silver are in this sample?
soldi70 [24.7K]

Answer:

14.3878 x 10^23 molecules Ag

Explanation:

2.39 mol Ag     6.02 x 10^23

----------------- x   ------------------ =  14.3878 x 10^23 Molecules Ag

     1                        1 mol

4 0
3 years ago
How do you balance REDOX reaction in acidic medium?
Mrrafil [7]
Hi there! I was looking at this a few days ago for school and found this 

5 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST
dedylja [7]

Answer:

In order to be able to solve this problem, you will need to know the value of water's specific heat, which is listed as

c=4.18Jg∘C

Now, let's assume that you don't know the equation that allows you to plug in your values and find how much heat would be needed to heat that much water by that many degrees Celsius.

Take a look at the specific heat of water. As you know, a substance's specific heat tells you how much heat is needed in order to increase the temperature of 1 g of that substance by 1∘C.

In water's case, you need to provide 4.18 J of heat per gram of water to increase its temperature by 1∘C.

What if you wanted to increase the temperature of 1 g of water by 2∘C ?

This will account for increasing the temperature of the first gram of the sample by n∘C, of the the second gramby n∘C, of the third gram by n∘C, and so on until you reach m grams of water.

And there you have it. The equation that describes all this will thus be

q=m⋅c⋅ΔT , where

q - heat absorbed

m - the mass of the sample

c - the specific heat of the substance

ΔT - the change in temperature, defined as final temperature minus initial temperature

In your case, you will have

q=100.0g⋅4.18Jg∘C⋅(50.0−25.0)∘C

q=10,450 J

4 0
3 years ago
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