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seropon [69]
3 years ago
7

100.mL of a .795 M solution of KBr is diluted to 500.mL. what is the new concentration of the solution?

Chemistry
1 answer:
kap26 [50]3 years ago
4 0

Answer:

0.159 M

Explanation:

convert from mL to L then use the equation:

M1V1 = M2V2

rearrange to find M2

\frac{M1V1}{V2} = M2

\frac{(0.795 M)(0.100 L)}{0.500 L} = 0.159 M

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Consider the titration of 40.0 mL of 0.400 M HI by 0.300 M NaOH. Calculate the pH after 41.1 mL of NaOH has been added. pH = 1.3
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6 0
4 years ago
What volume of a 0.155 M potassium hydroxide solution is required to neutralize 25.7 mL of a 0.388 M hydrobromic acid solution
vekshin1

Answer: Therefore, the volume of a 0.155 M potassium hydroxide solution  is 56.0 ml

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

According to the neutralization law,

n_1M_1V_1=n_2M_2V_2

where,

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n_1 = valency of HBr = 1

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V_2=56.0ml

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