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3 years ago

Propane burns in oxygen to produce carbon dioxide and water what is the percent yeild

Chemistry

1 answer:

amid [387]3 years ago

4 0

Answer:

The percentage yield is 78.2g

Explanation:

Given, mass of propane = 42.8 g , sufficient O2 percent yield = 61.0 % yield.

Reaction - C3H8(g)+5O2(g)------> 3CO2(g)+4H2O(g)

First we need to calculate the moles of propane

Moles of propane = $\frac{42.8}{44.096}$ g.mol-1

= 0.971 moles

So, moles of CO2 from the moles of propane

1 mole of C3H8(g) = 3 moles of CO2(g)

So, 0.971 moles of C3H8(g) = ?

= 2.913 moles of CO2

So theoretical yield = 2.913 moles $\times$ 44.0 g/mol

= 128.2 g

So, the actual mass of CO2 = percent yield $\times$ theoretical yield / 100 %

= 61.0 % $\times$ 128.2 g / 100 %

= 78.2 g

the mass of CO2 that can be produced if the reaction of 42.8 g of propane and sufficient oxygen has a 61.0 % yield is 78.2 g

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Calculate the mass of H2OH2O produced by metabolism of 2.4 kgkg of fat, assuming the fat consists entirely of tristearin (C57H11

otez555 [7]

Answer:

2,669.58 grams of water will be produced by metabolism of 2.4 kilogram of fat.

Explanation:

$2C_{57}H_{110}O_6+163O_2\rightarrow 114CO_2+110H_2O$

Mass of fat = 2.4 kg = 2.4 × 1000 g = 2400 g

1 kg = 1000 g

Molar mass of fat = M

M = 57 × 12 g/mol + 110 × 1 g/mol+ 6 × 16 g/mol = 890 g/mol[/tex]

Moles of fat = $\frac{2400 g}{890 g/mol}=2.6966 mol$

According to reaction , 2 moles of fat gives 110 moles of water. Then 2.6966 moles of fat will give ;

$\frac{110}{2}\times 2.6966 mol=148.31 mol$ of water

Mass of 148.31 moles of water ;

148.31 mol × 18 g/mol = 2,669.58 g

2,669.58 grams of water will be produced by metabolism of 2.4 kilogram of fat.

8 0

3 years ago

Choose a likely identity for X, Y, and Z in these structures. A central X atom is bonded to two chlorine atoms through single bo

natka813 [3]

Complete Question

The complete question is shown on the first uploaded image

Answer:

X is Be

Y is B

Z is O

Explanation:

In order to understand the solution, we need to that the an element form a bond based on

1 The number of valence electron available in its atom

2 The number of electron it require to attains its stable state i.e its Octet state

The number of valence electron for each of the option are

F = 7, N = 5 , O = 6 , C = 4 , B = 3 , Be = 2

Considering the first element

We see that X is donating two valence electron in its atom and it is donating it to 2 Cl as Cl only requires a single electron to achieve its stable state

Now looking option we can see that Be has two valence electron in it atom and in order for it to attain its stable state it needs to release the electron so the correct option for this question is Be

Considering the second element

We see that Y is donating three valence electron in its atom and it is donating it to 3 Cl as Cl only requires a single electron to achieve its stable state

Now looking option we can see that B has three valence electron in it atom and in order for it to attain its stable state it needs to release the valence electron so the correct option for this question is B

Considering the second element

We see that Z is donating two valence electron in its atom and it is donating it to 2 Cl as Cl only requires a single electron to achieve its stable state, also Z has 2 lone-pair valence electron

Now looking at the option we can see that O has 6 valence electron so if it donates 2 valence electron it will still be left with 4 - pair of electron

Therefore the correct option to this question is O

6 0

3 years ago

2) Which liberates the most energy?

evablogger [386]

Answer: $F(g)+e^-\rightarrow F^-(g)$

Explanation:

Electron gain enthalpy is defined as energy released on addition of electron to an isolated gaseous atom.

The amount of energy released will be maximum when the tendency to attract electrons is maximum. As flourine has atomic number of 9 and has electronic configuration of 2,7. It can readily gain 1 electron to attain stable noble gas configuration and hence liberates maximum energy.

$F(g)+e^-\rightarrow F^-(g)$

4 0

3 years ago

Consider this reaction:

Brilliant_brown [7]

Answer : The oxidation state of Mg in Mg(s) is (0).

Explanation :

Oxidation number or oxidation state : It represent the number of electrons lost or gained by the atoms of an element in a compound.

Oxidation numbers are generally written with the sign (+) and (-) first and then the magnitude.

Rules for Oxidation Numbers are :

The oxidation number of a free element is always zero.

The oxidation number of a monatomic ion equals the charge of the ion.

The oxidation number of Hydrogen (H) is +1, but it is -1 in when combined with less electronegative elements.

The oxidation number of oxygen (O) in compounds is usually -2.

The oxidation number of a Group 17 element in a binary compound is -1.

The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.

The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.

The given chemical reaction is:

$Mg(s)+2H_2O(l)\rightarrow Mg(OH)_2(s)+H_2(g)$

In the given reaction, the oxidation state of Mg in Mg(s) is (0) because it is a free element and the oxidation state of Mg in $Mg(OH)_2$ is (+2).

Hence, the oxidation state of Mg in Mg(s) is (0).

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3 years ago

A chemical change is like a physical change because no new substance is formed. Agree or DIsagree and reason why

aleksandrvk [35]

I disagree, because a physical change changes the form, and a chemical change is a process where one or more substances are altered into new substances.

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3 years ago