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Setler79 [48]
2 years ago
8

Plot ΔABC on graph paper with points A(3,3), B(1,1), and C(6,1). Reflect ΔABC by multiplying the y-coordinates of the vertices b

y −1. Then use the function (x,y)→(x−6,y−3) to translate the resulting triangle. Name the coordinates of the vertices of the result.
Question 3 options:

A'(-3,3), B'(-1,1), C'(-1,6)


A'(-6,-3), B'(-4,-5), C'(-4,0)


A'(3,-3), B'(1,-1), C'(6,-1)


A'(-3,-6), B'(-5,-4), C'(0,-4)


Plot ΔABC on graph paper with points A(10,4), B(-1,1), and C(4,2). Reflect ΔABC by multiplying the x-coordinates of the vertices by −1. Then use the function (x,y)→(x−5,y+4) to translate the resulting triangle. Name the coordinates of the vertices of the result.

Question 4 options:

A'(-4,-10), B'(-1,1), C'(-2,-4)


A'(-8,15), B'(-5,4), C'(-6,1)


A'(-10,4), B'(1,1), C'(-4,2)


A'(-15,8), B'(-4,5), C'(-9,6)
Mathematics
1 answer:
MAXImum [283]2 years ago
6 0

Answer:

First one would be D (( A'(-3,-6), B'(-5,-4), C'(0,-4) ))

The second would be D (( A'(-15,8), B'(-4,5), C'(-9,6) )) as well

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Answer:

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valina [46]

Answer:

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Step-by-step explanation:

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3 0
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NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.
Aleks [24]

Answer:

A.) 24.08 seconds

B.) 825.42 metres

Step-by-step explanation:

function of time is given as

h ( t ) = − 4.9 t 2 + 118 t + 115 .

Where a = -4.9, b = 118, c = 115

Let's assume that the trajectory of the rocket is a perfect parabola.

The time t the rocket will reach its maximum height will be at the symmetry of the parabola.

t = -b/2a

Substitute b and a into the formula

t = -118/-2(4.9)

t = 118/9.8

t = 12.041 seconds

Since NASA launches the rocket at t = 0 seconds, the time it will splash down into the ocean will be 2t.

2t = 2 × 12.041 = 24.08 seconds

Therefore, the rocket splashes down after 24.08 seconds.

B.) At maximum height, time t = 12.041s

Substitute t for 12.041 in the function

h ( t ) = − 4.9 t 2 + 118 t + 115

h(t) = -4.9(12.041)^2 + 118(12.041) + 115

h(t) = -4.9(144.98) + 118(12.041) + 115

h(t) = -710.402 + 1420.82 + 115

h(t) = 825.42 metres

Therefore, the rocket get to the peak at 825.42 metres

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a class survey showed 8 out of 25 students had plans to travel over spring break. how many students out of the 400 students in t
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Traveling : total
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x : 400 

25 x 4 = 400 so 8 x 4 = 40 so the answer is 40. 
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Kris is 2 meters tall and casts a shadow
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The tree is 20 m tall .

Step-by-step explanation:

<h2>Given : </h2>
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=> 2 m tree = 4 m long

If we find shadow of 1 m tall tree = 4/2

=> we have to find height of 10 m tall tree which is .. = 4/2 × 10 = > 20 m

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2 years ago
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