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3 years ago

Simplify. 6(y+13)+21y

1 answer:

5 0

Simplifying 6y + 1 = 21y + 13

Reorder the terms: 1 + 6y = 21y + 13
Reorder the terms: 1 + 6y = 13 + 21y

Solving 1 + 6y = 13 + 21y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-21y' to each side of the equation. 1 + 6y + -21y = 13 + 21y + -21y

Combine like terms: 6y + -21y = -15y 1 + -15y = 13 + 21y + -21y

Combine like terms: 21y + -21y = 0 1 + -15y = 13 + 0 1 + -15y = 13

Add '-1' to each side of the equation. 1 + -1 + -15y = 13 + -1

Combine like terms: 1 + -1 = 0 0 + -15y = 13 + -1 -15y = 13 + -1
Combine like terms: 13 + -1 = 12 -15y = 12
Divide each side by '-15'. y = -0.8
Simplifying y = -0.8

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Urgent help! This is very important please help me fast! How do you do: Expand & simplify:(x 4)(x 2)

ahrayia [7]

So the question is asking: (x-4)(x-2)
because there is a bracket in between the two expressions it means we have to multiply them together: (x-4) x (x-2)

you can break down the question into smaller parts:
x multiply x
x multiply -2
-4 multiply x
-4 multiply -2

here are the answers:
x^2 (means x squared)
-2x
-4x
8 (because when you multiply two negative numbers it makes a positive)

now you put it into an expression (this is expanding):
x^2 - 2x - 4x + 8

to simplify it you collect like terms:
x^2 - 6x + 8

The above is the answer :)

4 0

3 years ago

I need help on 24 please

charle [14.2K]

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4 0

3 years ago

((-2^2)(-1^-3))•((-2^-3)(-1^5))^-2

Vitek1552 [10]

Answer:

256

Step-by-step explanation:

A calculator works well for this.

_____

None of the minus signs are subject to the exponents (because they are not in parentheses, as (-1)^5, for example. Since there are an even number of them in the product, their product is +1 and they can be ignored.

1 to any power is still 1, so the factors (1^n) can be ignored.

After you ignore all of the things that can be ignored, your problem simplifies to ...

(2^2)(2^-3)^-2

The rules of exponents applicable to this are ...

(a^b)^c = a^(b·c)

(a^b)(a^c) = a^(b+c)

Then your product simplifies to ...

(2^2)(2^((-3)(-2)) = (2^2)(2^6)

= 2^(2+6)

= 2^8 = 256

3 0

3 years ago

Find the value of a and of b for which (a) the solution of x2 + ax -2<x < 4

KengaRu [80]

Answer: $a = -2$

$b = 8$

Step-by-step explanation:

Given :

$x^{2} +ax$

re - writing the equation , we have

$x^{2} +ax-b$

we need to find the value of a and b for which -2<x < 4 , this means that the roots of the quadratic equation are -2<x < 4.

The formula for finding the quadratic equation when the roots are known is :

$x^{2}$ - sum of roots(x) + product of root = 0

sum of roots = -2 + 4 = 2

product of roots = -2 x 4 = -8

substituting into the formula , we have:

$x^{2} -2x-8=0$ , which could be written in inequality form as

$x^{2} -2x-8$

comparing with $x^{2} +ax-b$ , it means that :

$a = -2$

$b = 8$

3 0

3 years ago

a square has the side measurment of s = 2 3 over 2 using the formula 1= s^2 find the area of the square

vitfil [10]

Check the picture below.

$\bf A=s^2\qquad s=2\frac{3}{2}\qquad A=\left( 2\frac{3}{2} \right)^2\implies A=\left( \frac{2\cdot 2+3}{2} \right)^2
\\\\\\
A=\left( \frac{7}{2} \right)^2\implies A=\cfrac{7^2}{2^2}\implies A=\cfrac{49}{4}\implies A=12\frac{1}{4}$

3 0

3 years ago