What energy allows for the difference in the spacing of molecules in a liquid versus a gas?

This is a material that allows heat/electricity to transfer.

Anvisha [2.4K]

A material that allows heat/electricity to transfer is called a conductor.

5 0

3 years ago

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When you squeeze an air-filled balloon, what happens inside?

Harman [31]

Option D

When you squeeze an air-filled balloon, what happens inside: There are more collisions of air molecules against the wall of the balloon.

Explanation:

If you compress off the balloon, one seemingly sense the air forcing up on the wall of the balloon with indeed more imposing power. This rise in force is due to a drop in quantity. By squeezing the balloon, you lessen the area the gas bits can hold.

As the particles are driven a little closer collectively, they oppose more, so the force from the moving gas bits rises. Boyle’s Law pronounces that the quantity of a determined quantity of gas limits as its load rises. If the quantity rises, its load reduces.

4 0

3 years ago

Consider the reaction N2(g) + 2O2(g)2NO2(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surr

zysi [14]

Answer: The value of $\Delta S^o$ for the surrounding when given amount of nitrogen gas is reacted is 231.36 J/K

Explanation:

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

$\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]$

For the given chemical reaction:

$N_2+2O_2\rightarrow 2NO_2$

The equation for the entropy change of the above reaction is:

$\Delta S^o_{rxn}=[(2\times \Delta S^o_{(NO_2(g))})]-[(1\times \Delta S^o_{(N_2(g))})+(2\times \Delta S^o_{(O_2(g))})]$

We are given:

$\Delta S^o_{(NO_2(g))}=240.06J/K.mol\\\Delta S^o_{(O_2)}=205.14J/K.mol\\\Delta S^o_{(N_2)}=191.61J/K.mol$

Putting values in above equation, we get:

$\Delta S^o_{rxn}=[(2\times (240.06))]-[(1\times (191.61))+(2\times (205.14))]\\\\\Delta S^o_{rxn}=-121.77J/K$

Entropy change of the surrounding = - (Entropy change of the system) = -(-121.77) J/K = 121.77 J/K

We are given:

Moles of nitrogen gas reacted = 1.90 moles

By Stoichiometry of the reaction:

When 1 mole of nitrogen gas is reacted, the entropy change of the surrounding will be 121.77 J/K

So, when 1.90 moles of nitrogen gas is reacted, the entropy change of the surrounding will be = $\frac{121.77}{1}\times 1.90=231.36 J/K$

Hence, the value of $\Delta S^o$ for the surrounding when given amount of nitrogen gas is reacted is 231.36 J/K

7 0

4 years ago

Vitamin C contains the elements C, H, and O. It is known to contain 40.9% C and 4.58% H by mass. The molar mass of vitamin C has

soldier1979 [14.2K]

Answer:

C₆H₈O₆

Explanation:

First off, the percent of oxygen by mass of vitamin C is:

100 - (40.9+4.58) = 54.52 %

Assume we have one mol of vitamin C. Then we would have 180 grams, of which:

180 * 40.9/100 = 73.62 grams are of Carbon

180 * 4.58/100 = 8.224 grams are of Hydrogen

180 * 54.52/100 = 98.136 grams are of Oxygen

Now we convert each of those masses to moles, using the elements' respective atomic mass:

C ⇒ 73.62 g ÷ 12 g/mol = 6.135 mol C ≅ 6 mol C

H ⇒ 8.224 g ÷ 1 g/mol = 8.224 mol H ≅ 8 mol H

O ⇒ 98.136 g ÷ 16 g/mol = 6.134 mol O ≅ 6 mol O

So the molecular formula for vitamin C is C₆H₈O₆

8 0

3 years ago

Help with this chemistry worksheet

viktelen [127]

Answer:

1. is exothermic

Explanation:

5 0

4 years ago

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