Answer:
Explanation:
The table is:
<em>Star Light Years from the Sun</em>
<em>Chara 27.3 light years</em>
<em>Tau Ceti 11.9 light years</em>
<em>Zeta Leporis 70.2 light years</em>
<em>Epsilon Reticuli 59.5 light years</em>
<em>Light years</em> is a unit of distance. It is the distance that the light travels in one year.
Since the speed of light is a constant, ≈ 300,000,000 m/s, one light year is equal to the product of
by the number of seconds in a year (about 31,540,000 seconds).
Thus, the smaller the number of light years a star is from the Sun the closer the distance between the star and the Sun.
Rank the distances in increasing order:
Then, Tau Ceti, with 11.9 light years is the closest to the Sun.
Answer:
1. 2.510kJ
2. Q = 1.5 kJ
Explanation:
Hello there!
In this case, according to the given information for this calorimetry problem, we can proceed as follows:
1. Here, we consider the following equivalence statement for converting from calories to joules and from joules to kilojoules:
Then, we perform the conversion as follows:
2. Here, we use the general heat equation:
And we plug in the given mass, specific heat and initial and final temperature to obtain:
Regards!
Answer : The work done by the system is, 2.2722 J
Explanation :
The expression used for work done in reversible isothermal expansion will be,
where,
w = work done = ?
n = number of moles of gas = 0.00100 mole
R = gas constant = 8.314 J/mole K
T = temperature of gas =
= initial volume of gas = 25 mL
= final volume of gas = 75 mL
Now put all the given values in the above formula, we get:
Therefore, the work done by the system is, 2.2722 J