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Kisachek [45]
3 years ago
11

Balance Cl2+NaBr=NaCl+Br2​

Chemistry
1 answer:
kvasek [131]3 years ago
5 0
Cl2 + 2NaBr → 2NaCl + Br2
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I need help solving this for chemistry. Don’t know where to start:/
Juli2301 [7.4K]
1 electron has charge =1.602* 10⁻¹⁹ C
1 mole of electrons have 1.602* 10⁻¹⁹*6.02*10²³C = 9.64*10⁴ C/1mol

One ion Co²⁺   takes 2e⁻ to become Co⁰.
1 mol of Co²⁺  ions take 2 mole of e⁻ to become Co⁰, so
 0.30 mol Co²⁺  ions take mole of 0.60 mol e⁻ to become Co⁰

9.64*10⁴(C/1mol) *0.60 (mol)≈ 5.8 *10⁴ Coulombs.
Correct answer is C
8 0
3 years ago
Look at the following enthalpy diagram. Select all that apply.
Drupady [299]

Answer:

Option 2 and 4 are correct

Explanation:

The reactants in the attached image have more enthalpy and hence less stability as they are more reactive. Thus, Product is more stable than the reactants.

This is an addition reaction in which two reactants add up to form the product.

Very less activation energy is required as the reactants themselves are unstable, possess high energy and hence are very reactive.

Reactants have more energy than the products.  

5 0
3 years ago
Classify each of the following reactions as either exothermic or endothermic: 2H,O(l) + heat → 2H₂(g) + O₂(g)​
Murljashka [212]

Answer:

endothermic

Explanation:

It is endothermic since it absorbs heat.  If the reaction RELEASED heat (exothermic) the "+ heat" would be on the right side of the equation.

6 0
1 year ago
Which has the highest electronegativity value?
AnnZ [28]
Which has the highest electronegativity value?
A
hydrogen

B
calcium

C
helium

D
fluorine d because fluorine has a higher group number

8 0
3 years ago
2. Suppose that 21.37 mL of NaOH is needed to titrate 10.00 mL of 0.1450 M H2SO4 solution.
AysviL [449]

Answer:

0.1357 M

Explanation:

(a) The balanced reaction is shown below as:

2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O

(b) Moles of H_2SO_4 can be calculated as:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Or,

Moles =Molarity \times {Volume\ of\ the\ solution}

Given :

For H_2SO_4 :

Molarity = 0.1450 M

Volume = 10.00 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 10×10⁻³ L

Thus, moles of H_2SO_4 :

Moles=0.1450 \times {10\times 10^{-3}}\ moles

Moles of H_2SO_4  = 0.00145 moles

From the reaction,

1 mole of H_2SO_4 react with 2 moles of NaOH

0.00145 mole of H_2SO_4 react with 2*0.00145 mole of NaOH

Moles of NaOH = 0.0029 moles

Volume = 21.37 mL = 21.37×10⁻³ L

Molarity = Moles / Volume = 0.0029 /  21.37×10⁻³  M = 0.1357 M

7 0
3 years ago
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