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viktelen [127]
4 years ago
12

{Plz answer} Thank you!

Chemistry
2 answers:
Dafna11 [192]4 years ago
8 0

The Answer to your question would be A

Umnica [9.8K]4 years ago
7 0

I would say A. Hope this helps, and cya! :3

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What is 6.9 x 10^-3 in standard form?
Maslowich

Answer:

0.0069

Explanation:

When converting between scientific notation try to remember that moving the decimal place to the left is positve and to the right is negative

Since you are changing from scientific to standard you will need to move to the left from the decimal point, making your answer 0.0069

4 0
3 years ago
Copper reacts with silver nitrate through single replacement.
-Dominant- [34]

Answer:

  • Part a) 0.0104 moles copper(II) nitrate.

  • Part b)

            i) 0.0418 mole Cu

            ii) 0.0209 mol Ag NO₃

Explanation:

<u>1) Balanced chemical reaction (single replacement):</u>

In a single replacement reaction a more acitve metal (Cu) replaces a less active metal (Ag)

  • Cu + 2 Ag NO₃ → Cu (NO₃)₂ + 2 Ag

<u>2) Mole ratio: </u>

  • 1 mole Cu : 2 mole Ag NO₃ : 2 mole Ag

<u />

<u>3) Moles of Ag</u>

  • n = mass in grams / atomic mass
  • atomic mass of Ag: 107.868 g/mol
  • n = 2.25 g / 107.868 g/mol = 0.0209 mol Ag

<u>4) Moles of copper(II) nitrate:</u>

  • Set the proportion using the mole ratio:
  • 2 mole Ag / 1 mole Cu (NO₃)₂ = 0.0209 mole Ag / x
  • Solve: x = 0.0209 / 2 mole Cu (NO₃)₂ =  0.0104 moles Cu(NO₃)₂

That is the answer of part a: 0.0104 moles copper(II) nitrate.

<u>5) Moles of each reactant</u>

i) Cu:

  • Set a proportion using the theoretical mole ratio

        1 mole Cu / 2 mole Ag = x / 0.0209 mol Ag

  • Solve for x: x = 0.0209 / 2 mole Cu = 0.0418 mole Cu

ii) Ag NO₃

  • Set a proportion using the teoretical mole ratio

   

       2 mole Ag NO₃ / 2 mole Ag = x / 0.0209 mole Ag

  • Solve for x: x = 0.0209 mol Ag NO₃
6 0
4 years ago
Name the parts of an electromagnet
Oxana [17]

Answer:

The iron core, copper wire, and an electricity source.

Explanation: Me

7 0
3 years ago
A helium filled ballon had a volume of 8.50 L on the ground at 20.0 C and a pressure of 750.0 Torr. After the ballon was release
Marrrta [24]

Answer:

V_2=12.1L

Explanation:

Hello!

In this case, according to the given data of volume, pressure and temperature, it is possible to infer this problem can be solved via the combined gas law:

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

Thus, regarding the question, we evidence we need V2, but first we make sure the temperatures are in Kelvins:

T_1=20+273=293K\\\\T_2=-40+273=233K

Then, we obtain:

V_2=\frac{P_1V_1T_2}{T_1P_2}\\\\V_2=\frac{0.987atm*8.50L*233K}{293K*0.550atm}\\\\V_2=12.1L

Best regards!

5 0
3 years ago
Physical Science pre-Test 2020-2021
poizon [28]

Answer:

exothermic I think

Explanation:

IM TWKIGN THE TEST

4 0
3 years ago
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