Let's assume two variables x and y which represent the local and international calls respectively.
x + y = 852 = total number of minutes which were consumed by the company (equation 1)
0.06*x+ 0.15 y =69.84 = total price which was charged for the phone calls (Equation 2)
from equation 1:-
x=852 -y (sub in equation 2)
0.06 (852 - y) + 0.15 y =69.84
51.12 -0.06 y +0.15 y =69.84 (subtracting both sides by 51.12)
0.09 y =18.74
y= 208 minutes = international minutes (sub in 1)
208+x=852 (By subtracting both sides by 208)
x = 852-208 = 644 minutes = local minutes
So, he runs 1.5 then adds 0.5 every day,
1.5
(1.5+0.5)+1.5=x
(2.0+0.5)+x=z
2.5+0.5+z=y
etc.
Why, they want to know the total distance he runs, so thats why you add x,y,z to the end, and you add 2.0+0.5 because he adds 0.5 every dat Plus the other day's miles jogged
Answer:
Step-by-step explanation:
x²+7x-11=-5x+6
x²+7x+5x-11-6=0
x²+12x-17=0
Answer:
![f(g(x))=\frac{1}{(x^{2}+1)^{2}} +\sqrt[3]{x^{2}+1}](https://tex.z-dn.net/?f=f%28g%28x%29%29%3D%5Cfrac%7B1%7D%7B%28x%5E%7B2%7D%2B1%29%5E%7B2%7D%7D%20%2B%5Csqrt%5B3%5D%7Bx%5E%7B2%7D%2B1%7D)
Step-by-step explanation:
we have
![f(x)=x^{2} +\frac{1}{\sqrt[3]{x}}](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B2%7D%20%2B%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7Bx%7D%7D)
we know that
In the function
The variable of the function f is now the function g(x)
substitute
![f(g(x))=(\frac{1}{x^{2}+1})^{2} +\frac{1}{\sqrt[3]{(\frac{1}{x^{2}+1})}}](https://tex.z-dn.net/?f=f%28g%28x%29%29%3D%28%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%2B1%7D%29%5E%7B2%7D%20%2B%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7B%28%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%2B1%7D%29%7D%7D)
Answer:
x = 40
Step-by-step explanation:
Angles SRT and STR are congruent, so they have the same measure.
The measure of <SRT is 20, so the measure of <STR is also 20.
Angles STR and STU form a linear pair. Two angles that form a linear pair are supplementary, so their measures add up to 180.
m<STR + m<STU = 180
20 + 4x = 180
4x = 160
x = 40
