Warm front Forms when a moist, warm airmass slides up and over a cold air mass. As the warm airmass rises, it condenses into a broad area of clouds. A warmfront brings gentle rain or light snow, followedby warmer, milder weather.
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Answer:
Im like 75% sure that the answer is C.
Explanation:
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Answer:
z≅3
Atomic number is 3, So ion is Lithium ion (
)
Explanation:
First of all
v=f*λ
In our case v=c
c=f*λ
λ=c/f
where:
c is the speed of light
f is the frequency
![\lambda=\frac{3*10^8}{2.961*10^{16}}\\ \lambda=1.01317*10^{-8} m](https://tex.z-dn.net/?f=%5Clambda%3D%5Cfrac%7B3%2A10%5E8%7D%7B2.961%2A10%5E%7B16%7D%7D%5C%5C%20%5Clambda%3D1.01317%2A10%5E%7B-8%7D%20m)
Using Rydberg's Formula:
![\frac{1}{\lambda}=R*z^2*(\frac{1}{n_1^2}-\frac{1}{n_2^2})](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Clambda%7D%3DR%2Az%5E2%2A%28%5Cfrac%7B1%7D%7Bn_1%5E2%7D-%5Cfrac%7B1%7D%7Bn_2%5E2%7D%29)
Where:
R is Rydberg constant=![1.097*10^7](https://tex.z-dn.net/?f=1.097%2A10%5E7)
z is atomic Number
For highest Energy:
n_1=1
n_2=∞
![\frac{1}{1.01317*10^{-8}}=1.097*10^{7}*z^2*(\frac{1}{1^2}-\frac{1}{\inf})\\z^2=8.99\\z=2.99](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B1.01317%2A10%5E%7B-8%7D%7D%3D1.097%2A10%5E%7B7%7D%2Az%5E2%2A%28%5Cfrac%7B1%7D%7B1%5E2%7D-%5Cfrac%7B1%7D%7B%5Cinf%7D%29%5C%5Cz%5E2%3D8.99%5C%5Cz%3D2.99)
z≅3
Atomic number is 3, So ion is Lithium ion (
)
What is the question and are there answers to go with it