Explanation:
The answer is
153.7
k
J
.
What you are asked to determine is the total energy required to go from ice to water, and then from water to vapor - the phase changes underwent by the water molecules.
In order to do this, you'll need to know:
Heat of fusion of water:
Δ
H
f
=
334
J
/
g
;
Heat of fusion vaporization of water:
Δ
H
v
=
2257
J
/
g
;
Specific heat of ice:
c
=
2.09
J
/
g
∘
C
;
Specific heat of water:
c
=
4.18
J
/
g
∘
C
;
Specific heat of steam:
c
=
2.09
J
/
g
∘
C
;
So, the following steps describe the overall process:
1. Determine the heat required to raise the temperature of the ice from
−
15.0
∘
C
to
0
∘
C
:
q
1
=
m
⋅
c
i
c
e
⋅
Δ
T
=
50.0
g
⋅
2.09
J
g
⋅
∘
C
⋅
(
0
∘
C
−
(
−
15
∘
C
)
)
=
1567.5
J
2. Determine the heat required to convert
0
∘
C
ice to
0
∘
C
water:
q
2
=
m
⋅
Δ
H
f
=
50.0
g
⋅
334
J
g
=
16700
J
3. Determine the heat required to go from water at
0
∘
C
to water at
100
∘
C
:
Answer:
1.atomic number
2.electron
3.element
4.atom
5.neutron
6.nucleus
7.proton
Explanation:
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Answer:
The volume of a given gas sample is directly proportional to its absolute temperature at constant pressure (Charles's law). The volume of a given amount of gas is inversely proportional to its pressure when temperature is held constant (Boyle's law).
Answer:
4.5 × 10⁻⁹
Explanation:
Step 1: Write the reaction for the solution of CaCO₃
CaCO₃(s) ⇄ Ca²⁺(aq) + CO₃²⁻(aq)
Step 2: Convert the solubility of CaCO₃ from g/L to mol/L
We will use the following conversion factors:
- The molar mass of CaCO₃ is 100.09 g/mol.
- 1 L= 1000 mL.
- There are 0.00067 g of CaCO₃ per 100 mL of solution.
Step 3: Calculate the solubility product constant (Ksp)
To relate Ksp and the molar solubility (S), we need to make an ICE chart.
CaCO₃(s) ⇄ Ca²⁺(aq) + CO₃²⁻(aq)
I 0 0
C +S +S
E S S
The solubility product constant is:
Ksp = [Ca²⁺].[CO₃²⁻] = S² = (6.7 × 10⁻⁵)² = 4.5 × 10⁻⁹