Answer:
lateral area ≈ 668 m²
surface area ≈ 740 m²
Step-by-step explanation:
The lateral area of a triangular prism = perimeter of the base × height of the prism
lateral area = ph
where
p = perimeter of the base
h = height or altitude
Base edges are 8m , 9m and 12.04m and height is 23 m.
lateral area = ph
lateral area = (8 + 9 + 12.04) × 23
lateral area = 29.04 × 23
lateral area = 667.92 m²
lateral area ≈ 668 m²
Surface area
surface area = lateral area + 2B
where
B = area of it triangular bases
surface area = lateral area + 2B
surface area = 667.92 + 2(1/2 × base × height)
surface area = 667.92 + 2(1/2 × 8 × 9)
surface area = 667.92 + 2(1/2 × 72)
surface area = 667.92 + 2(36)
surface area = 667.92 + 72
surface area = 739.92
surface area ≈ 740 m²
Divide each term by U and simplify. X=y/U and W=2/U. Next, solve the equation for y. Simplify the left side then cancel the common factor of U. 1/1*y/1=y
W=2/U. Multiply 1/1*y/1=y/1 so, y/1=y and W=2/U. Next, divide y/y to get 1 now y=y, still W=2/U. Now, move all terms containing y to the left side. Since, Y contains the variable to solve for, move it to the left side of the equation by subtracting y from both sides. Now, y-y=0 still W=2/U. Next, subtract y from y to get zero and still W=2/U. Subtract y from y to get zero or 0=0 and W=2/U is your expression since 0=0.
Next: UW=m and WX=y+14 write expression for UX
First, divide each term by W and simplify. U=m/W, WX=y+14. Next, solve the equation for Y. Move y from the right side of the equation to the left side. Still, U=m/W and y=-14+WX. We must reorder -14 and WX. U=m/w and y=WX-14.
Replace the variable U with m/W in the expression to (m/W)X. Next, simplify (m/W)X. Now, write X and a fraction with denominator 1. Looks like this
fractions are side by side m/W X/1 . Multiply, m/W and X/1 to get mX/W.
mX/W is your final expression for UW=m and WX=y+14 expression for UX.
The graph below represents y < 2 over 3x − 2 | <span>y > 2x + 2</span> system of inequalities. The answer is letter C. The rest of the choices do not answer teh qustion above
