PLEASE HELP ME!!!
1 answer:
The reason for that is that P-waves (primary waves) travel faster than S-waves (secondary waves).
If we call
the speed of the primary waves and 
the speed of the secondary waves, and we call 
the distance of the seismogram from the epicenter, we can write the time the two waves take to reach the seismogram as
So the lag time between the arrival of the P-waves and of the S-waves is
We see that this lag time is proportional to the distance S, therefore the larger the distance, the greater the lag time.
If we call
So the lag time between the arrival of the P-waves and of the S-waves is
We see that this lag time is proportional to the distance S, therefore the larger the distance, the greater the lag time.
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Answer:
vB = 15.4 m/s
Explanation:
Principle of conservation of energy:
Because there is no friction the mechanical energy is conserve
ΔE = 0
ΔE : mechanical energy change (J)
K : Kinetic energy (J)
U: Potential energy (J)
K = (1/2)mv²
U = m*g*h
Where :
m: mass (kg)
v : speed (m/s)
h : hight (m)
Ef - Ei = 0
(K+U)final - (K+U)initial =0
(K+U)final = (K+U)initial
((1/2)mv²+m*g*h)final = ((1/2)mv²+m*g*h)initial , We divided by m both sides of the equation:
((1/2)vB² + g*hB = (1/2 )vA²+ g*hA
(1/2) (vB)² + (9.8)*(14.7) = 0 + (9.8)(26.8 )
(1/2) (vB)² = (9.8)(26.8 ) - (9.8)*(14.7)
(vB)² = (2)(9.8)(26.8 - 14.7)
(vB)² = 237.16
vB = 15.4 m/s : speed of the cart at B
Answer:
-26 m/s.
Explanation:
Hello,
In this case, since the vertical initial velocity is 26 m/s and the vertical final velocity is 0 m/s at P, we compute the time to reach P:
With which we compute the maximum height:
Therefore, the final velocity until the floor, assuming P as the starting point (Voy=0m/s), turns out:
Which is clearly negative since it the projectile is moving downwards the starting point.
Regards.