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valkas [14]
3 years ago
12

PLEASE HELP ME!!!

Physics
1 answer:
denis-greek [22]3 years ago
6 0
The reason for that is that P-waves (primary waves) travel faster than S-waves (secondary waves).

If we call v_p the speed of the primary waves and v_s the speed of the secondary waves, and we call S the distance of the seismogram from the epicenter, we can write the time the two waves take to reach the seismogram as
t_P =  \frac{S}{v_P}
t_S= \frac{S}{v_S}

So the lag time between the arrival of the P-waves and of the S-waves is
\Delta t = t_S-t_P= \frac{S}{v_S}- \frac{S}{v_P}= S(\frac{1}{v_S}- \frac{1}{v_P})
We see that this lag time is proportional to the distance S, therefore the larger the distance, the greater the lag time.
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