PLEASE HELP ME!!!
1 answer:
The reason for that is that P-waves (primary waves) travel faster than S-waves (secondary waves).
If we call
the speed of the primary waves and 
the speed of the secondary waves, and we call 
the distance of the seismogram from the epicenter, we can write the time the two waves take to reach the seismogram as
So the lag time between the arrival of the P-waves and of the S-waves is
We see that this lag time is proportional to the distance S, therefore the larger the distance, the greater the lag time.
If we call
So the lag time between the arrival of the P-waves and of the S-waves is
We see that this lag time is proportional to the distance S, therefore the larger the distance, the greater the lag time.
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Answer:
100 miles North East.
Explanation:
Please see attached photo for diagram.
In the attached photo, X represents the magnitude of the total displacement of the train.
Thus, we can obtain the value of X by using the pythagoras theory as illustrated below:
X² = 80² + 60²
X² = 6400 + 3600
X² = 10000
Take the square root of both side
X = √10000
X = 100 miles.
Therefore, the magnitude of the total displacement of the train is 100 miles North East.
Answer:
<em>The internal energy change is 330.01 J</em>
Explanation:
Given
the initial volume = 5.75 L
the final volume = 1.23 L
is the external pressure = 1.00 atm
q the heat energy removed = -128 J (since is removed from the system)
expansion against a constant external pressure is an example of an irreversible pathway, here pressure in is greater than pressure out and can be obtained thus;
W = -ΔV
W = -1.00 x(1.23 - 5.75)
W = -1.00 x -4.52
W = 4.52 L atm
converting to joules we have
W = 4.52 L atm x 101.33 J/ L atm = 458.01 J
The internal energy change during compression can be calculated thus;
ΔU = q + W
ΔU = -128 J + 458.01 J
ΔU = 330.01 J
Therefore the internal energy change is 330.01 J