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3 years ago

PLEASE HELP ME!!!

1 answer:

6 0

The reason for that is that P-waves (primary waves) travel faster than S-waves (secondary waves).

If we call $v_p$ the speed of the primary waves and $v_s$ the speed of the secondary waves, and we call $S$ the distance of the seismogram from the epicenter, we can write the time the two waves take to reach the seismogram as
$t_P = \frac{S}{v_P}$
$t_S= \frac{S}{v_S}$

So the lag time between the arrival of the P-waves and of the S-waves is
$\Delta t = t_S-t_P= \frac{S}{v_S}- \frac{S}{v_P}= S(\frac{1}{v_S}- \frac{1}{v_P})$
We see that this lag time is proportional to the distance S, therefore the larger the distance, the greater the lag time.

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Give proof that mass is constant and weight keeps changing.

shutvik [7]

The mass of an object stays the same wherever it is, but its weight can change. This happens if the object goes where the gravitational field strength is different from the gravitational field strength on Earth, such as into space or another planet.

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2 years ago

What is the natural frequency (wo) of a circuit that has an inductor of 0.048 henery's, and a capacitor of 0.0004 farads?

adell [148]

Answer:

The natural frequency will be 228.11 rad/sec

Explanation:

We have given Inductance L = 0.048 Henry

And the capacitance C = 0.0004 farad

We have to find natural frequency

When only inductor and capacitor is present in the circuit then it is known as LC circuit and Natural frequency of LC circuit is given by $\omega _0=\frac{1}{\sqrt{LC}}=\frac{1}{\sqrt{0.048\times 0.0004}}=228.21\ rad/sec$

So the natural frequency will be 228.21

4 0

3 years ago

A car and a truck are moving next to each other on the highway. The truck has a mass of 910 kg and the car’s mass is 227 kg. IF

eimsori [14]

Answer:

<h2>the car must move with the speed</h2><h2> $v = 72.16 m/s$ </h2>

Explanation:

As we know that the momentum of the car and truck is same

so as per the formula of momentum we have

$P = mv$

so we have

$m_1v_1 = m_2v_2$

so we will have

$910 \times 18 = 227 v$

$v = 72.16 m/s$

So the car must move with the speed

$v = 72.16 m/s$

3 0

3 years ago

If you were to walk with a speed if 2m/s for 2 hours how far would you travel

olga nikolaevna [1]

So simply it to 120m/m for 120 minutes. So then you multiply 120x120 and that equals 14,400

7 0

3 years ago

brainly an andean condor with a wingspan and a mass soars along a horizontal path. model its wings as a rectangle with a width.

Anna35 [415]

The difference between the pressure at the top surfaces of the condor's wings and the pressure at the bottom surfaces is 101,204 Pa.

<h3>Difference in pressure between the top and bottom of the wingspan</h3>

The difference in pressure between the top and bottom of the wingspan is calculated as follows;

ΔP = P(top) - P(bottom)

<h3>Area of the wingspan</h3>

A = bh

A = 2.7 m x 0.27 m

A = 0.729 m²

<h3>Weight of the Andean condor</h3>

W = mg

W = 9 x 9.8

W = 88.2 N

<h3>Pressure at the top surface of condor's wings</h3>

The pressure at the top surface of condor's wings is due to atmospheric pressure

P(top) = 14.7 Psi = 101,325 Pa

<h3>Pressure at the bottom surface of condor's wings</h3>

The pressure at the bottom surface is due to weight of andean condor.

P = W/A

P(bottom) = 88.2/0.729

P(bottom) = 120.99 Pa

The difference between the pressure at the top surfaces of the condor's wings and the pressure at the bottom surfaces is calculated as;

ΔP = P(top) - P(bottom)

ΔP = 101,325 Pa - 120.99 Pa

ΔP = 101,204 Pa

The complete question is below;

An Andean condor with a wingspan of 270 cm and a mass of 9.00 kg soars along a horizontal path. Model its wings as a rectangle with a width of 27.0 cm.

Learn more about pressure here: brainly.com/question/25736513

5 0

2 years ago