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love history [14]
3 years ago
9

Which of the following objects is in dynamic equilibrium? A - a man standing in one place without moving B- a bicycle accelerati

ng forward at 1.25 m/s^2 C- a car driving in a circle at a constant speed of 20 m/s D- a motorcycle with a constant velocity
Physics
2 answers:
Bas_tet [7]3 years ago
5 0
The answer is <span>D- a motorcycle with a constant velocity.

Velocity is much more stable in terms of speed and distance that can be associated with the dynamics of equilibrium (balance) compared to speed alone. It brings the constant relationship between the two elements. 

Speed is only focused on time of travel and not with direction. While acceleration does not show equilibrium but only a change in speed.
</span>
Anettt [7]3 years ago
3 0

Answer:

Option (D)

Explanation:

A dynamic equilibrium is the state in which the net force on the body is zero but the body is moving.

For option (a), A man is standing without moving, it means the man is in static equilibrium.

For option (b), a bicycle accelerating forward with acceleration, it means it is not in dynamic equilibrium.

For option (c), a car driving in circle with a constant speed, it means the direction of speed is changing, so the acceleration is there and the car is not in dynamic equilibrium.

For option (d), a motorcycle with a constant velocity, it means the net force is zero and the motorcycle is in dynamic equilibrium.

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A gas at a pressure of 2.10 atm undergoes a quasi static isobaric expansion from 3.70 to 5.40 L. How much work is done by the ga
BartSMP [9]

Answer:

Total work done in expansion will be 3.60\times 10^5J

Explanation:

We have given pressure P = 2.10 atm

We know that 1 atm =1.01\times 10^5Pa

So 2.10 atm =2.10\times 1.01\times 10^5=2.121\times 10^5Pa

Volume is increases from 3370 liter to 5.40 liter

So initial volume V_1=3.70liter

And final volume V_2=5.40liter

So change in volume dV=5.40-3.70=1.70liter

For isobaric process work done is equal to W=PdV=2.121\times 10^5\times 1.70=3.60\times 10^5J

So total work done in expansion will be 3.60\times 10^5J

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2 years ago
Calculate the pressure exerted on the floor when an elephant who weighs 6000 N stands on one foot which has an area of 20 m2
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Answer:

300 Pascal

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area (A) = 20 m²

pressure (p) = ?

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= 300 Pascal

Hope it will help :)

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3 years ago
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