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love history [14]
3 years ago
9

Which of the following objects is in dynamic equilibrium? A - a man standing in one place without moving B- a bicycle accelerati

ng forward at 1.25 m/s^2 C- a car driving in a circle at a constant speed of 20 m/s D- a motorcycle with a constant velocity
Physics
2 answers:
Bas_tet [7]3 years ago
5 0
The answer is <span>D- a motorcycle with a constant velocity.

Velocity is much more stable in terms of speed and distance that can be associated with the dynamics of equilibrium (balance) compared to speed alone. It brings the constant relationship between the two elements. 

Speed is only focused on time of travel and not with direction. While acceleration does not show equilibrium but only a change in speed.
</span>
Anettt [7]3 years ago
3 0

Answer:

Option (D)

Explanation:

A dynamic equilibrium is the state in which the net force on the body is zero but the body is moving.

For option (a), A man is standing without moving, it means the man is in static equilibrium.

For option (b), a bicycle accelerating forward with acceleration, it means it is not in dynamic equilibrium.

For option (c), a car driving in circle with a constant speed, it means the direction of speed is changing, so the acceleration is there and the car is not in dynamic equilibrium.

For option (d), a motorcycle with a constant velocity, it means the net force is zero and the motorcycle is in dynamic equilibrium.

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It would have to be 36,719 Km high in order to be to be in geosynchronous orbit.

To find the answer, we need to know about the third law of Kepler.

<h3>What's the Kepler's third law?</h3>
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<h3>What's the radius of geosynchronous orbit, if the time period and altitude of ISS are 90 minutes and 409 km respectively?</h3>
  • The time period of geosynchronous orbit is 24 hours or 1440 minutes.
  • As the Earth's radius is 6371 Km, so radius of the ISS orbit= 6371km + 409 km = 6780km.
  • If T1 and T2 are time period of geosynchronous orbit and ISS orbit respectively, a1 and a2 are radius of geosynchronous orbit and ISS orbit, as per third law of Kepler, (T1/T2)² = (a1/a2)³
  • a1= (T1/T2)⅔×a2

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Thus, we can conclude that the altitude of geosynchronous orbit is 36,719km.

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