1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
love history [14]
3 years ago
9

Which of the following objects is in dynamic equilibrium? A - a man standing in one place without moving B- a bicycle accelerati

ng forward at 1.25 m/s^2 C- a car driving in a circle at a constant speed of 20 m/s D- a motorcycle with a constant velocity
Physics
2 answers:
Bas_tet [7]3 years ago
5 0
The answer is <span>D- a motorcycle with a constant velocity.

Velocity is much more stable in terms of speed and distance that can be associated with the dynamics of equilibrium (balance) compared to speed alone. It brings the constant relationship between the two elements. 

Speed is only focused on time of travel and not with direction. While acceleration does not show equilibrium but only a change in speed.
</span>
Anettt [7]3 years ago
3 0

Answer:

Option (D)

Explanation:

A dynamic equilibrium is the state in which the net force on the body is zero but the body is moving.

For option (a), A man is standing without moving, it means the man is in static equilibrium.

For option (b), a bicycle accelerating forward with acceleration, it means it is not in dynamic equilibrium.

For option (c), a car driving in circle with a constant speed, it means the direction of speed is changing, so the acceleration is there and the car is not in dynamic equilibrium.

For option (d), a motorcycle with a constant velocity, it means the net force is zero and the motorcycle is in dynamic equilibrium.

You might be interested in
Pertaining to simple machines and levers what changes when the fulcrum position is modified?
Inessa [10]

Explanation :

There are many types of simple machines i.e. lever, wedge, pulley, wheel and axle etc.

Fulcrum is the pivot point about which the lever turns. When the position of the fulcrum is shifted, the position of effort changes.

There are three classes of the lever as class 1, class 2 and class 3.

Class 1 includes seesaws and scissors.

class 2 includes wheelbarrow

class 3 includes tongs and tweezers.

7 0
3 years ago
At room temperature, an oxygen molecule, with mass of 5.31x10^-26kg , typically has a kinetic energy of about 6.21x10^-21J. How
den301095 [7]

Answer:

V=483.63 m/s

Explanation:

Given that

mass ,m= 5.31 x 10⁻²⁶ kg

Kinetic energy KE= 6.21 x 10⁻²¹ J

As we know that the kinetic energy of the mass m with moving velocity V given as

KE=\dfrac{1}{2}mV^2  

Now by putting the values

6.21\times 10^{-21}=\dfrac{1}{2}\times 5.31\times 10^{-26}\times V^2

V^2=\dfrac{2\times 6.21\times 10^{-21}}{5.31\times 10^{-26}}

V^2=233898.30

V=\sqrt{233898.30}\ m/s

V=483.63 m/s

Therefore the velocity of the molecule at the room temperature will be 483.63 m/s.

6 0
4 years ago
Gravity and magnetism are both
ella [17]

Answer:

Explanation:

Comment

You have to read this carefully enough that you don't mix up energy and forces.

Gravity is a force. If you don't believe me try jumping off a building. Which way are you going to go and why? Down because gravity attracts your mass.

So Magnetism must be a force as well. It acts in one direction, but not a specific one the way gravity acts). It also either attracts or repulses (pushes an object away)

Answer A

3 0
2 years ago
Read 2 more answers
A 215-kg load is hung on a wire of length of 3.60 m, cross-sectional area 2.00 10-5 m2, and Young's modulus 8.00 1010 N/m2. What
Y_Kistochka [10]

Answer:

4.74 * 10^-3

Explanation:

6 0
3 years ago
On the surface of the earth the weight of an object is 200 lb. Determine the height of the
siniylev [52]

Answer:

The height of the  object is 5007.4 miles.

Explanation:

Given that,

Weight of object = 200 lb

We need to calculate the value of Gmm_{e}

Using formula of gravitational force

F=\dfrac{Gmm_{e}}{r^2}

Put the value into the formula

200=\dfrac{Gmm_{e}}{(3958.756)^2}

200\times(3958.756)^2=Gmm_{e}

Gmm_{e}=3.134\times10^{9}

We need to calculate the height of the  object

Using formula of gravitational force

F=\dfrac{Gmm_{e}}{r^2}

Put the value into the formula

125=\dfrac{200\times(3958.756)^2}{r^2}

r^2=\dfrac{200\times(3958.756)^2}{125}

r^2=25074798.5

r=\sqrt{25074798.5}

r=5007.4\ miles

Hence. The height of the  object is 5007.4 miles.

7 0
3 years ago
Other questions:
  • An alternating current consists of charges that ?
    6·1 answer
  • Explain an example of how energy is transferred from one form to another
    13·1 answer
  • A constant braking force of 10 newtons applied for 5 seconds is used to stop a 2.5-kilogram cart traveling at 20 meters per seco
    6·2 answers
  • Ryan swings a pail of water in a vertical circle 1.0 m in radius at a constant speed. If the water is NOT to spill on him:
    8·1 answer
  • What does erosion do to landforms and to sediment
    7·2 answers
  • Before leaving the house in the morning, you plop some stew in your slow cooker and turn it on Low. The slow cooker has a 160 Oh
    8·1 answer
  • Explain these speed-time and distance-time graphs in your own words
    5·1 answer
  • Convection currents will transfer heat throughout a gas until what condition arises?
    6·2 answers
  • 1. Which statement best describes the motion of the scooter? *
    7·1 answer
  • If I walk 30 m north and turn around and walk 10 m to the south, what is the magnitude
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!