In an elastic collision, two objects collide and return to their original positions with no loss of ________

3 write the three laws given by kepler.How did they help Newton to arrive at the inverse square law of gravity?

stiv31 [10]

Answer:

Kepler's laws apply: First Law: Planetary orbits are elliptical with the sun at a focus. Second Law: The radius vector from the sun to a planet sweeps equal areas in equal times. Third Law: The ratio of the square of the period of revolution and the cube of the ellipse semimajor axis is the same for all planets.

5 0

3 years ago

A 500 kg sports car accelerates uniformly from rest reaching a speed of 30 m/s in 6 seconds .Find the distance travelled by the

Dimas [21]

Answer:

the distance traveled by the sports car is 90 m

Explanation:

Given;

mass of the sports car, m = 500 kg

initial velocity of the sports car, u = 0

final velocity of the sport car, v = 30 m/s

time of motion of the car, t = 6 s

The distance traveled by the sports car is calculated as;

$s = (\frac{u+v}{2} )t\\\\s = (\frac{0+30}{2} ) \times 6\\\\s = 15 \times 6\\\\s = 90 \ m$

Therefore, the distance traveled by the sports car is 90 m

6 0

3 years ago

What is the mass of an object which has a force of 600 N acting on it and is travelling

Paha777 [63]

Answer:

<em>The mass of the object is 40 Kg</em>

Explanation:

<u>Net Force</u>

According to the second Newton's law, the net force exerted by an external agent on an object is:

F = m.a

Where:

a = acceleration of the object.

m = mass of the object.

The mass can be calculated by solving for m:

$\displaystyle m=\frac{F}{a}$

The object has a net force of F=600 N acting on it and travels at $a=15\ m/s^2$ , thus the mas is:

$\displaystyle m=\frac{600}{15}$

m = 40 Kg

The mass of the object is 40 Kg

6 0

2 years ago

A computational model predicts the maximum potential energy a roller coaster car can have given its mass and its speed at the lo

andreyandreev [35.5K]

Answer:

The prediction for its maximum potential energy is 109,375 J

Explanation:

Given;

mass of the coaster car, m = 350 kg

speed of the coaster car at the lowest point, v = 25 m/s

The coaster car will have maximum kinetic energy at the lowest point and based on law of conservation of mechanical energy, the maximum kinetic energy of the coaster car at the lowest point will be equal to maximum potential energy at the highest point.

$K.E_{max} = P.E_{max}$