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2 years ago

NEED HELP with 7. 8. 9. 10. 11. 12. And 14 !!

Chemistry

1 answer:

aleksley [76]2 years ago

6 0

Answer:

1. 0.00040 calories

2. 8.57 calories

3. 0.196 calories

4. 68 calories

5. 243 calories

6. 83680 joules

7. 1,054,368 joules

8. 2.45 calories

9. 556 (it says calories to calories so it wouldn't change)

10. 28367.52 joules

11. 59.6 calories

12. 449.6 joules

13. 0.00234 calories

14. 23292.328 joules

15. 22877693.6 joules

Hope this helps!

Explanation:

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Calculate freeze 62.9 g of iron at 1535oC<br> Hf (J/g)=257

Inessa [10]

Answer:

Explanation:

(257J/g)(62.9g)

eliminate the variables

u get 16165.3

go to 3 significant digits

u get 16200

and since it is freezing we are taking out energy so it would be

-16200J

4 0

3 years ago

12.Calculate the wavelength of an object moving with a velocity of 5 x105 m s-1

uranmaximum [27]

Answer:

Wavelength, $\lambda=3.3\times 10^{-18}\ m$

Explanation:

We have,

Velocity of the object, $v=5\times 10^5\ m/s$

Mass of the object, $m=4\times 10^{-22}\ kg$

It is required to find the wavelength of the object. The relation between wavelength and velocity of the object is given by :

$\lambda=\dfrac{h}{mv}$

h is Planck's constant

$\lambda=\dfrac{6.6\times 10^{-34}}{4\times 10^{-22}\times 5\times 10^5}\\\\\lambda=3.3\times 10^{-18}\ m$

So, the wavelength of the object is $3.3\times 10^{-18}\ m$ .

5 0

3 years ago

Determine the potential deaths resulting from the following exposure to chlorine:

jekas [21]

Answer:

For each scenario as following:

A. 3 Potential deaths by chlorine exposure

B. 1 Potential deaths by chlorine exposure

C. 3 Potential deaths by chlorine exposure

Explanation:

According to Freitag, 1941 Chlorine exposure can be lethal at the concentration of 34-51 ppm in a time of 1h-1.5h. The answers are based on his reference.

6 0

3 years ago

You are performing an experiment that uses 114Ag. 113Ag is radioactive, decays by beta-- emission and has a half-life of 21 minu

maxonik [38]

Answer: The 234.74 grams of sample should be ordered.

Explanation:

Let the gram of 114 Ag to ordered be $N_o$

The amount required for the beginning of experiment = 0.0575 g

Time requires to ship the sample = 4.2hour = 252 min(1 hr = 60 min)

Half life of the sample = ${t_{\frac{1}{2}}$ = 21 min

$\lambda =\frac{0.693}{t_{\frac{1}{2}}}=\frac{0.693}{21 min}=0.033 min^{-1}$

$\log[N]=\log[N_o]-\frac{\lambda t}{2.303}$

$\log[0.0575 g]=\log[N_o]-\frac{0.033 min^{-1}\times 252 min}{2.303}$

$N_o=234.74 grams$

The 234.74 grams of sample should be ordered.

4 0

2 years ago

What does a gamma ray primarily consist of?

damaskus [11]

Answer is D

Explanation: A gamma ray primarily consists of pure energy and no mass.

6 0

2 years ago