Hey... hey you.. psstt... can you help me in this exercise pls? It would mean everything.
2 answers:
55.5.
Since this is an irregular figure and you’re trying to solve for area, you would need to split it up into shapes, i.e. a rectangle and a triangle. You have the length and width of the rectangle, so in line with the area formula flr a rectangle: l•w=A, you would need to multiply 3 and 5 to get 15. As for the area of the triangle, you can see that it was a height of 9, because of the 3 inches you shave off, and a length of 9. To get the area of a triangle, multiply the length times the width and divide by 2. So (9•9)/2. That would give you 40.5, which you then add to 15 to get 55.5.
Since this is an irregular figure and you’re trying to solve for area, you would need to split it up into shapes, i.e. a rectangle and a triangle. You have the length and width of the rectangle, so in line with the area formula flr a rectangle: l•w=A, you would need to multiply 3 and 5 to get 15. As for the area of the triangle, you can see that it was a height of 9, because of the 3 inches you shave off, and a length of 9. To get the area of a triangle, multiply the length times the width and divide by 2. So (9•9)/2. That would give you 40.5, which you then add to 15 to get 55.5.
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Answer:
Choice D
Step-by-step explanation:
For this one I would find if the point lands on the line.
<em><u>Choice A:</u></em>
What we have to do is to plug in -4 for x and 4 for y.
The point is not on this line so this cannot be it.
<em><u>Choice B:</u></em>
We pug what we know again.
The point is not on this line so it can't be it.
<em><u>Choice C:</u></em>
We pug in what we know again.
The point is not on this line so it can't be it.
The next one has to be it, but we'll check it just in case.
<em><u>Choice D:</u></em>
We plug in what we know again.
The point is on this line so this is the line.