2 years ago

Couldn't copy and paste, so just screenshotted, pls help. will give brainly.

1 answer:

6 0

Answer: I could be wrong but according to Newton’s third law of motion, for every action, there is an equal and opposite action, so for every answer, just find an arrow that’s the same size as the blue one and make the arrow point in the opposite direction that the blue one is pointing to

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One positve and one negative charhe jave a force of -5. 00 N between them. If the force changed to -170 N , by what factor did t

stepladder [879]

Answer:

The distance is shortenend by factor .1715

Explanation:

5 n = 1/r^2

sqrt (1/5) = r

170 n = 1 / ( x sqrt(1/5))^2

(xsqrt 1/5)^2 = 1/170

x sqrt 1/5 = .076696

x = .1715

5 0

2 years ago

9.58 A spring of equilibrium length L1 and spring constant k1 hangs from the ceiling. Mass m1 is suspended from its lower end. T

andrey2020 [161]

Answer:

The distance of m2 from the ceiling is L1 +L2 + m1g/k1 + m2g/k1 + m2g/k2.

See attachment below for full solution

Explanation:

This is so because the the attached mass m1 on the spring causes the first spring to stretch by a distance of m1g/k1 (hookes law). This plus the equilibrium lengtb of the spring gives the position of the mass m1 from the ceiling. The second mass mass m2 causes both springs 1 and 2 to stretch by an amout proportional to its weight just like above. The respective stretchings are m2g/k1 for spring 1 and m2g/k2 for spring 2. These plus the position of m1 and the equilibrium length of spring 2 L2 gives the distance of L2 from the ceiling.