The unknown substance can be lithium, which has a specific heat capacity of approximately
.
Explanation:
When heat energy is supplied to a certain substance, the temperature of the substance increases according to the equation:

where
Q is the amount of energy supplied
m is the mass of the sample
is the specific heat capacity of the substance
is the change in temperature
In this problem, we have
m = 4.9 g is the mass
Q = 668.85 J is the specific heat capacity
is the change in temperature
Solving for
, we find the specific heat capacity of the substance:

Looking at tables of specific heat capacity, we can see that the unknown substance can be lithium, which has a specific heat capacity of approximately
.
Learn more about specific heat capacity:
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