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Nimfa-mama [501]
4 years ago
9

Amir observes Wave 1 and Wave 2 crashing into each other at two different intervals. His experiments produce Wave 3 and Wave 4.

Amir records his data in a table.
What is the best statement about the data collected in Amir’s table?


Wave 3 resulted from destructive interference, and Wave 4 resulted from constructive interference.


Waves 3 and 4 resulted from constructive interference.


Waves 3 and 4 resulted from destructive interference.


Wave 3 resulted from constructive interference, and Wave 4 resulted from destructive interference.

Physics
2 answers:
topjm [15]4 years ago
6 0

Answer:

"Wave 3 resulted from constructive interference and Wave 4 resulted from destructive interference."

Explanation:

Constructive Interference:

When two waves meet in such a way that their crests line up together, then it's called constructive interference. The resulting wave has a higher amplitude.

Destructive Interference:

In destructive interference, the crest of one wave meets the trough of another, and the result is a lower total amplitude.

The amplitude of Wave 3 is higher than both the Waves, 1 & 2, so it must be a result of constructive interference.

The amplitude of Wave 4 is less than both the Waves, 1 & 2, so it must be a result of destructive interference.

Leokris [45]4 years ago
6 0

Answer:

Wave 3 resulted from constructive interference and Wave 4 resulted from destructive interference."

Explanation:

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A container with volume 1.83 L is initially evacuated. Then it is filled with 0.246 g of N2. Assume that the pressure of the gas
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The  pressure is  P =   1652 \  Pa

Explanation:

From the question we are told that

    The  volume of the container is  V  =  1.83  \ L =  1.83 *10^{-3 } \  m^3

     The mass of  N_2 is  m_n  =  0.246 \ g =  0.246 *10^{-3} \ kg

     The root-mean-square velocity is  v =  192 \ m/s

The  root -mean square velocity is mathematically represented as

      v =  \sqrt{ \frac{3 RT}{M_n  } }

Now the ideal gas law is mathematically represented as

      PV  =  nRT

=>   RT  =  \frac{PV}{n }

Where n is the number of moles which is mathematically represented as

         n =  \frac{ m_n }{M }

Where  M  is the molar mass of  N_2

So  

        RT  =  \frac{PVM_n }{m _n  }

=>    v =  \sqrt{ \frac{3 \frac{P* V  *  M_n }{m_n } }{M_n  } }

=>    v =  \sqrt{  \frac{ 3 *  P* V  }{m_n } } }

=>   P =   \frac{v^2   *  m_n}{3 *    V  }

substituting values

    =>    P =   \frac{( 192)^2   *  0.246 *10^{-3}}{3 *    1.83 *10^{-3} }

=>         P =   1652 \  Pa

       

     

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3 years ago
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