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kogti [31]
3 years ago
14

An object acted on by three forces moves with constant velocity. One force acting on the object is in the positive xx direction

and has a magnitude of 6.9 N; a second force has a magnitude of 4.5 N and points in the negative y direction. Find the direction and magnitude of the third force acting on the object.
Physics
1 answer:
Rudik [331]3 years ago
8 0

Answer with Explanation:

We are given that

F_1=6.9 N

F_2=4.5 N

We have to find the direction and magnitude of the third force acting on the object.

Resultant force,F=\sqrt{F^2_1+F^2_2}

F=\sqrt{(6.9)^2+(4.5)^2}=8.24 N

The object moves with constant velocity .Therefore, net force on object is equal to zero

So,Third force,F_3=F=8.24 N

Direction,\theta=tan^{-1}(\frac{F_2}{F_1})

\theta=tan^{-1}(\frac{4.5}{6.9})=33.02^{\circ}

Angle lies in second quadrant because the direction of third force is opposite to the direction of the resultant force of F1 and F2.

Therefore,\theta=\pi-\theta=180-33.02=146.98^{\circ}

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Answer:

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Answer:

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Explanation:

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    From the graph attached,

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                                           = 90 meters

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    Average speed = \frac{90}{60}

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2). Velocity is a vector quantity.

    Therefore, average velocity = \frac{\triangle d}{\triangle t}

                                                   = \frac{d_{60}-d_0}{60-0}

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Convert 8.1 kilograms to grams
kirill115 [55]

Answer:

8100 g

Explanation:

8.1 kg × 1000

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6 0
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Given a wire with a cross section of .45cm^2, a length of 3cm, and an internal resistance of 3 ohms, show your 5 steps to solve
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pishuonlain [190]
When I find a problem like this, I find it helpful to think about what I know and what equation will help me.

The question tells us the frequency of the wave (5 \times 10^{-9}) Hz. We want to work out the wavelength. What equation links these two quantities?

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