In the absence of air resistance, a ball is thrown vertically upward with a certain initial KE. When air resistane is a factor a
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Answer:
(A) Distance taken by automobile to overtake truck is 175.23 m
(B) Final speed of the automobile is 29.6 m/s.
Explanation:
According to the problem, the automobile is at rest, so its initial speed is zero and the automobile is moving with constant acceleration.
The general equation of motion is:
d = ut + 0.5at² .....(1)
Here d is distance, a is acceleration, t is time and u is initial speed.
The distance (d₁) travel by the automobile after green light in time t is given by the relation :
d₁ = u₁t + 0.5at²
We know that its initial velocity is zero i.e. u = 0 m/s.
d₁ = 0.5at² ......(2)
The truck is moving with constant speed, so its acceleration is zero. Therefore, the distance covered by the truck using equation (1) is;
d₂ = u₂t .......(3)
Since, the distance travelled by automobile and truck are same. Hence,
d₁ = d₂
0.5at² = u₂t
t = 2u₂/a
Substitute 14.8 m/s for u₂ and 2.50 m/s² for a in the above equation.
t =
t = 11.84 s
(A) Distance travelled by automobile, d = u₂t =14.8 x 11.84 = 175.23 m
(B) Final speed of the automobile is given by the relation:
v = u + at
v = 0 + 2.50 x 11.84
v = 29.6 m/s