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kvv77 [185]
3 years ago
9

In the absence of air resistance, a ball is thrown vertically upward with a certain initial KE. When air resistane is a factor a

ffecting the ball, does it return to its original level with the same, less or more KE? Does your answer contradict the law of energy of conservation?
Physics
1 answer:
Ber [7]3 years ago
4 0

Answer:

Explanation:

A ball is thrown vertically upward with a certain Kinetic Energy in the absence of air resistance and while returning it experiences air resistance.

Air resistance causes the ball to lose its kinetic energy as it provides resistance which will convert some of its kinetic energy to heat energy.

So in a way total energy is conserved but not kinetic energy as some portion of it is lost in the form of heat.              

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A team of engineers is working together to design a new airplane. The team members each live in different cities. For which purp
Ierofanga [76]

Answer:

The internet is most useful to them because they use it to communicate.

Explanation:

If I were to send a message to my brother in Florida, through the internet, while I'm in Pennsylvania he would get it in minutes. On the other hand if I were going to meet him and then explain what I wanted to tell him in person it would take a much longer time.  

8 0
3 years ago
hovering mosquito is hit by a raindrop that is 45 times as massive and falling at 8.1 m/s , a typical raindrop speed. How fast i
Y_Kistochka [10]

Answer:

7.92 m/s

Explanation:

m_1 = Mass of raindrop = 45m_2

m_2 = Mass of mosquito

u_1 = Initial Velocity of raindrop = 8.1 m/s

u_2 = Initial Velocity of mosquito = 0 m/s

v = Velocity of center of mass

For elastic collision

m_1u_1 + m_2u_2 =(m_1 + m_2)v\\\Rightarrow v=\frac{m_1u_1 + m_2u_2}{m_1 + m_2}\\\Rightarrow v=\frac{45m_2\times 8.1 + m_2\times 0}{45m_2 + m_2}\\\Rightarrow v=\frac{364.5m_2}{46m_2}\\\Rightarrow v=7.92\ m/s

Hence, the velocity of the attached mosquito, falling immediately afterward is 7.92 m/s

4 0
3 years ago
An object has a kinetic energy of 14 J and a mass of 17 kg , how fast is the object<br> moving?
Vlad1618 [11]
Use the formula:

E = (1/2) * m * v ^2

For unit consistency, make sure that:

E energy is in joules (J)
m mass is in kilograms (kg)
v velocity is in meters per second (m/s)
So, substituting to the equation:

14= (1/2) * (17) * v^2

By algebraic manipulation, we derive:

v = (2*14/17)^0.5

v = 1.2834 m/s
1.9K viewsView 4 Upvoters
Related Questions (More Answers Below)
5 0
3 years ago
Read 2 more answers
In large cities, much of the land is covered in asphalt and concrete. These materials keep water from touching the soil undernea
Zielflug [23.3K]

They become flooded

Explanation:

Pavements using concretes and asphalts make water to runoff their surface. These surfacing materials prevents infiltration of water into the soil.

  • Usually from every precipitation, a proportions goes into the soil as infiltration.
  • Paved surfaces prevents infiltration of water into the soil.
  • All the surface runoff will eventually move into nearby streams and rivers thereby increasing the volume of water in them.
  • This enables rivers to become inundated and in the process they flood their banks and surrounding areas.

Learn more:

Flooding brainly.com/question/1820994

#learnwithBrainly

3 0
3 years ago
You collect some data on horse racing along a straight track. You are able to fit the motion of the horse to a function during t
Digiron [165]

Answer:

The equation is missing in the question. The equation is $10 m  + 5(m/s^2)t^2+3(m/s^3)t^3$

a). $v=10 t +9t^2$ , the horse will not turn.

b). a(t) = 10 + 18t

Explanation:

Given :

$x(t)=10 m  + 5(m/s^2)t^2+3(m/s^3)t^3$

∴ At t =0, x = 10 m

a). Velocity as a function of time

$v = \frac{dx}{dt} $

  = $10 t +9t^2$

Turning velocity must be zero.

v(t) = 0

$10 t +9t^2=0$

$\therefore t = 0 \text{ or}\ t =-\frac{10}{9}$

Taking the positive value of time.

The horse will not turn.

b). Acceleration as a function of time.

$a(t)=\frac{dv}{dt}$

     = 10 + 18t

∴ a(t) = 10 + 18t

6 0
4 years ago
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