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Elena L [17]
4 years ago
9

How many protons does a rubidium atom have

Physics
2 answers:
Lana71 [14]4 years ago
8 0
37 I  hope I helped any :)
inna [77]4 years ago
3 0
It has 37 protons. ^_^
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A 75.5-kg person puts on a life jacket, jumps into the water, and floats. The jacket has a volume of 3.38 x 10-2 m3 and is compl
Andreyy89

Answer:

Density of jacket will be 680.4733kg/m^3

Explanation:

We know that weight of water displaced= buoyant force=weight of man

Now volume of water displaced v=3.38\times 10^{-2}+6.42\times 10^{-2}=9.8\times 10^{-2}m^3

Density of water d=100kg/m^3

So weight of water displaced =9.8\times 10^{-2}\times 1000=98kg

So weight of jacket = 98-75 = 23 kg

We have given volume of the jacket = 3.38\times 10^{-2}m^3

So density of jacket =\frac{mass}{volume}=\frac{23}{3.38\times 10^{-2}}=680.4733kg/m^3

6 0
3 years ago
Use differentials to estimate the amount of metal in a closed cylindrical can that is 10 cm high and 10 cm in diameter if the me
lana66690 [7]

Answer:

dV = 32.98 cm³

Explanation:

We know that

V = f ( h,r)

dV= \frac{\partial V}{\partial r}dr+ \frac{\partial V}{\partial h}dh

We also know that

V=\pi r^2h

dV= 2\pi h dr + \pi r^2 dh

Given that

h= 10 cm

d=10 cm ,  r= 5 cm

Thickness = 0.05 cm so  dr = 0.05 cm

The metal in the top and the bottom is 0.2 cm thick  so dh = 0.2 + 0.2 cm

dh = 0.4 cm

Now by putting the values

dV= 2\pi h dr + \pi r^2 dh

dV= 2\times \pi \times 5\times 0.05 + \pi \times 5^2\times 0.4\ cm^3

dV = 32.98 cm³

8 0
3 years ago
 An ultrasound pulse used in medical imaging has a frequency of 5 MHz and a pulse width of 0.5 us. Ap- proximately how many osci
podryga [215]

At the frequency of 5 MHz, the period of the oscillations is 1/5meg. That's a period of 1/5 microsecond.

There are 5 full cycles in one full microsecond, and there are 2.5 full cycles in a 0.5 us pulse.

You'll have to decide for yourself how damped a pulse of 2.5 cycles is, because the parameters of the definition are corrupted in the question.

4 0
3 years ago
Which single force acts on a object in a free fall
11Alexandr11 [23.1K]

Answer:

weight!!!! Free fall is the motion of a body where its weight is the only force acting on an object.

4 0
3 years ago
An experiment is performed aboard the International Space Station to verify that linear momentum is conserved during collisions
Anni [7]

Answer:

v=15.9554\ m.s^{-1}

Explanation:

Given:

  • mass of the honey drop 1, m_1=35.5\times 10^{-3}\ kg
  • velocity of the honey drop 1, v_1=13.1\ m.s^{-1}
  • mass of the honey drop 2, m_1=52.3\times 10^{-3}\ kg
  • velocity of the honey drop 2, v_2=14.5\ m.s^{-1}
  • mass of the honey drop 3, m_1=75.7\times 10^{-3}\ kg
  • velocity of the honey drop 3, v_3=18.3\ m.s^{-1}

<em>In ISS there is zero gravity an the collision is completely inelastic.</em>

<u>So, applying the law of conservation of momentum:</u>

m_1.v_1+m_2.v_2+m_3.v_3=(m_1+m_2+m_3).v

35.5\times 10^{-3}\times 13.1+52.3\times 10^{-3}\times 14.5+75.7\times 10^{-3}\times 18.3=(35.5+52.3+75.7)\times 10^{-3}\times v

v=15.9554\ m.s^{-1}

4 0
3 years ago
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