Answer:
The statement that is true is;
The vertices of the image are closer to the origin than those of the pre-image
Step-by-step explanation:
The dilation rule is 0.75(x,y)= (0.75x, 0.75y)
K (-4,4)----------( 0.75*-4,0.75*4)-------K' (-3,3)
L (2,4)-----------(0.75*2,0.75*4)---------L' (1.5,3)
M (-2,2)----------(0.75*-2,0.75*2)--------M' (-1.5,1.5)
Answer:
Given
Step-by-step explanation:
Given that: △RST ~ △VWX, TU is the altitude of △RST, and XY is the altitude of △VWX.
Comparing △RST and △VWX;
TU ~ XY (given altitudes of the triangles)
<TUS = <XYW (all right angles are congruent)
<UTS ≅ <YXW (angle property of similar triangles)
Thus;
ΔTUS ≅ ΔXYW (congruent property of similar triangles)
<UTS + <TUS + < UST = <YXW + <XTW + <XWY = (sum of angles in a triangle)
Therefore by Angle-Angle-Side (AAS), △RST ~ △VWX
So that:
=
(corresponding side length proportion)