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PolarNik [594]
3 years ago
12

A random sample of 100 college students is taken from the student body of a large university Assume that, in fact, a population

mean of 20 hours and a standard deviation of 15 hours describe the weekly study estimates for the entire student body. Therefore, the sampling distribution of the mean has a mean that:________.
a) approximates 20 hours.
b) equals 20 hours.
c) lies within a couple of hours of 20.
d) equals the one observed sample mean.
Mathematics
1 answer:
mixas84 [53]3 years ago
6 0

Answer:

b) equals 20 hours.

Step-by-step explanation:

The sampling distribution of means refers to the distribution of all the possible sample means, with a certain sample size (in this case, n=100) extracted from the population.

The sampling distribution of the means is equal to the population mean. That does not mean that every sample will result in a mean equal to the population, but that the population of sample means will have an average of 20 hours.

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konstantin123 [22]

Answer:

x=90 y=24

Step-by-step explanation:

I'm pretty sure if you're using slope this should be it.

7 0
3 years ago
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A students grade goes from a 95 to a 60 in 3 weeks. Calculate the students rate of grade change.
adoni [48]

Answer: The rate of change is 11.6666...

Step-by-step explanation:

You subtract 95 by 60 and you get 35.

You divide it by 3 because it happened over 3 weeks.

After dividing your answer is 11.6666...

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3 years ago
A certain city's population is 120,000 and decreases 1.4% per year for 15 years.
mart [117]

Answer:

  • Decay Problem.
  • Decay rate,  r = 0.014
  • Initial Amount =120,000
  • P(t)=120000(0.986)^t
  • P(10)=104,220

Step-by-step explanation:

The exponential function for growth/decay is given as:

P(t)=P_0(1 \pm r)^t, where:\\P_0$ is the Initial Population\\r is the growth/decay rate\\t is time

In this problem:

The city's initial population is 120,000 and it decreases by 1.4% per year.

  • Since the population decreases, it is a Decay Problem.
  • Decay rate, r=1.4% =0.014
  • Initial Amount =120,000

Therefore, the function is:

P(t)=120000(1 - 0.014)^t\\P(t)=120000(0.986)^t

When t=10 years

P(10)=120000(0.986)^10\\=104219.8\\\approx 104220 $ (to the nearest whole number)

8 0
3 years ago
Excel computes a two‑sample confidence interval for the difference in proportions just as well and as easily as Minitab and othe
True [87]

Answer:

See ecplanation below

Step-by-step explanation:

False.

On the Data analysis tool from excel we can conduct the following procedures:

Anova: Single Factor

Anova: Two factor with replication

Anova: Two factor without replication

Correlation

Covariance

Descriptive statistics

Exponential smoothing

F-test Two sample for Variances

Fourier analysis

Histogram

Moving Average

Random number generation

Rank and percentile

Regression

Sampling

t test: Paired two sample for means

t tes: Two sample assuming equal variances

t test: Two sample Assuming Unequal Variances

z test: Two sample for means

And as we can see we don't have an specific procedure just to obtain confidence interval for the difference of proportions. We need to remember that if we select a z test in excel, for example the output will contain the confidence associated to the parameter, but for this case is not too easy obtain a confidence interval for the difference of proportion like on a statistical software as (Minitab, R, SAS, etc) since all of these statistical softwares are elaborated in order to conduct all the possible statistical tests and confidence intervals for parameters of interest.

5 0
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This week, Michael collected $468 for delivering newspapers. He had 40 repeat customers and 18 new ones. As an incentive, he cha
loris [4]
468=40x+18(x-3)
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522=58x
9=x
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7 0
3 years ago
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