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Stella [2.4K]
3 years ago
11

there are Thirty coins and they are all dimes and nickels, and they are worth $2.60. How many nickles and dimes are there

Mathematics
1 answer:
Alla [95]3 years ago
5 0

Answer:

22 dimes, 8 Nickels

Step-by-step explanation:

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What is the area of the triangle?
Roman55 [17]

Answer:

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5 0
3 years ago
Is 40% of a class are girls. and 25% of girls play tennis, what is the percent of the class play tennis?
ASHA 777 [7]

Answer: a. 10%

Step-by-step explanation:

Girls in the class = 40%

Girls play tennis = 25%

Percentage of class play tennis = 40%*25% = 0.4*0.25 = 0.1

Percentage of class play tennis = 10%

5 0
3 years ago
Read 2 more answers
Jose makes $10000 a month plus some money by commission rates. He gets 6% of everything he sells. If Jose sold $59000 worth of i
IgorC [24]

Answer:

$13540

Step-by-step explanation:

Divide 100 from $59000 in which you get 1% of that worth.  If he gets 6% of that commission rate then he would get $3540 since 1% is $590 and you multiply by 6 to get that number.  Since he makes $10000 a month as stated, you would then add the amount $3540 for his salary to get $13540.

3 0
3 years ago
Read 2 more answers
The total number of people at a football game was 5600. Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.
rewona [7]

Answer:

1100 field-side tickets and 4500 end-zone tickets.

Step-by-step explanation:

Let x represent number of field side tickets and y represent number of end-zone tickets.

We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:

x+y=5600...(1)

y=5600-x...(1)    

We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.

Cost of x field side tickets would be 40x and cost of y end-zone tickets would be 20y.

The total amount of money received for the tickets was $134000. We can represent this information in an equation as:

40x+20y=134000...(2)

Upon substituting equation (1) in equation (2), we will get:

40x+20(5600-x)=134000

40x+112000-20x=134000

20x+112000=134000

20x+112000-112000=134000-112000

20x=22000

\frac{20x}{20}=\frac{22000}{20}

x=1100

Therefore, 1100 field side tickets were sold.

Upon substituting x=1100 in equation (1), we will get:

y=5600-1100

y=4500

Therefore, 4500 end-zone tickets were sold.

3 0
3 years ago
Given the function g(x) = 4(3)x, Section A is from x = 1 to x = 2 and Section B is from x = 3 to x = 4.
Rudik [331]
The question is defective, or at least is trying to lead you down the primrose path.
The function is linear, so the rate of change is the same no matter what interval (section) of it you're looking at.
The "rate of change" is just the slope of the function in the section.  That's
         (change in f(x) ) / (change in 'x') between the ends of the section.
In Section A:Length of the section = (1 - 0) = 1f(1) = 5f(0) = 0change in the value of the function = (5 - 0) = 5Rate of change =            (change in the value of the function) / (size of the section) = 5/1  =  5
In Section B:Length of the section = (3 - 2) = 1 f(3) = 15f(2) = 10change in the value of the function = (15 - 10) = 5Rate of change =           (change in the value of the function) / (size of the section) = 5/1  =  5
Part A:The average rate of change of each section is 5.
Part B:The average rate of change of Section B is equal to the average rate of change of Section A.
Explanation:The average rates of change in every section are equalbecause the function is linear, its graph is a straight line,and the rate of change is just the slope of the graph.

4 0
3 years ago
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