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OlgaM077 [116]
3 years ago
13

I messed up sorry

Mathematics
1 answer:
boyakko [2]3 years ago
8 0

Answer:

x2/5=3/20 it is the equation

and when we solve it

x2/5=3/20

x2/5×5/2=3/20×5/2

x=15/40 when we simplify it by 5 it is

x=3/9 it is the answer for the question.

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Answer:

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a rectangle is 8cm longer then it is wide, and it’s area is 153cm^2. Find the dimensions of the rectangle.
Stolb23 [73]

Answer:

Width of 9cm and length of 17cm.

Step-by-step explanation:

To calculate an area of a rectangle, use the formula A=l*w. We know the length is 8cm longer than the width. So l = 8 + w. So the area is A= (8+w)*w.

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153 = (8+w)(w)\\153 = 8w+w^2\\w^2+8w-153 = 0

To solve the quadratic, use the quadratic formula:

\frac{-b+/-\sqrt{b^2-4ac} }{2a}

Here a=1, b=8 and c=-153.

w=\frac{-b+/-\sqrt{b^2-4ac} }{2a} \\w=\frac{-8+/-\sqrt{8^2-4(1)(-153)} }{2(1)} \\w=\frac{-8+/-\sqrt{64+612} }{2} \\w=\frac{-8+/-\sqrt{676} }{2} \\w=\frac{-8+/-26 }{2} \\w=\frac{-8+26 }{2}=\frac{18}{2}=9 \\and\\w=\frac{-8-26 }{2} =\frac{-34}{2}=-17

Since w=9 or w=-17, substitute this value for w in l= 8+w to find l.

l = 8+9 = 17

or

l=8+-17 = -9

Since length cannot be positive, it must be l=17 and w=9.

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