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gavmur [86]
3 years ago
5

Consider the nuclear equation below. Superscript 222 subscript 86 upper R n right arrow superscript 218 subscript question mark

upper P o plus superscript 4 subscript 2 upper H e. Which is the missing value that will balance the equation? 84 86 88 90

Chemistry
2 answers:
Romashka-Z-Leto [24]3 years ago
7 0

Answer:

it is 84!

Explanation:

7nadin3 [17]3 years ago
3 0

Answer:

84

Explanation:

From the question given above, it is evident that 222 86Rn is emitting alpha particle since the daughter nuclei produced has a mass number lesser than 4 when compared to parent element.

Therefore, the miss value in the equation is 84.

Please see attachment for further details

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Tim wants to store 0.122 moles of helium gas at 203 kPa and 401 K. Which is the volume of the helium gas needed for storage?
algol13

 The  volume  of Helium gas needed for storage  is 2.00 L (answer C)


 <u><em> calculation</em></u>

 The volume of Helium is calculated using ideal gas equation

That is Pv =nRT

where;

 P( pressure) = 203 KPa

V(volume)=?

n(number  of moles) =  0.122 moles

R(gas constant) = 8.314  L.Kpa/mol.K

T(temperature)= 401 K

make V the  subject of the formula  by diving both side  by P

V=nRT/p

V={[0.122  moles x 8.314 L. KPa/mol.K  x 401 K]  / 203 KPa} = 2.00 L


3 0
3 years ago
A solution was prepared by dissolving 2.2 g of an unknown solute in 16.7 g of CCl4. A thermal analysis was performed for this so
laila [671]

Answer:

Molar mass of unknown solute is 679 g/mol

Explanation:

Let us assume that the solute is a non-electrolyte.

For a solution with non-electrolyte solute remains dissolved in it -

Depression in freezing point of solution, \Delta T_{f}=K_{f}.m

where, m is molality of solute in solution and K_{f} is cryogenoscopic constant of solvent.

Here \Delta T_{f}=(-22.9^{0}\textrm{C})-(-28.7^{0}\textrm{C})=5.8^{0}\textrm{C}

If molar mass of unknown solute is M g/mol then-

                 m=\frac{\frac{2.2}{M}}{0.0167}mol/kg

So, 5.8^{0}\textrm{C}=29.9^{0}\textrm{C}/(mol/kg)\times \frac{\frac{2.2g}{M}}{0.0167}mol/kg

so, M = 679 g/mol

4 0
3 years ago
If you need to reverse the following reaction in order for it to be an intermediate reaction in a Hess's law problem, what would
Olin [163]
When reversing a given reaction, we simply change the sign of the standard enthalpy change value. Therefore, the reaction will become:
H₂O → H₂ + 0.5O₂, ΔH = 286kJ
This is because if a certain amount of energy is released when a reaction occurs, the same amount of energy must be supplied for the reaction to occur in the reverse direction.
4 0
3 years ago
Read 2 more answers
You are given an unknown gaseous binary compound (that is, a compound consisting of two different elements). when 10.0 g of the
Luda [366]

Answer is: a possible identity for the unknown compound is C₃H₈.

m(binary compound) = 10.0 g.

m(H₂O) = 16.3 g; mass of water.

M(O₂) = 32 g/mol; molar mass of oxygen.

M(binary compound) = 1.38 · 32 g/mol.

M(binary compound) = 44.16 g/mol.

n(binary compound) = 10 g ÷ 44.16 g/mol.

n(binary compound) = 0.225 mol; amount of substance.

n(H₂O) = 16.3 g ÷ 18 g/mol.

n(H₂O) = 0.9 mol; amount of water.

m(H₂O) : n(binary compound) = 0.9 mol ÷ 0.225 mol.

m(H₂O) : n(binary compound) = 4 : 1.

Unknown cpmpound has 4 times more hydrogen than water, it has 8 hydrogen atoms.

Second element in compound is carbon:

M(X) = 44.16 g/mol - 8 · 1.01 g/mol.

M(X) = 36.08 g/mol ÷ 3.

M(C) = 12.01 g/mol.

8 0
3 years ago
PLZ HELP ASAP!!!
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