C. both a and b
If a light bulb can last longer with the same amount of energy it is given, that means it can use less energy to do the same job compared to one that does not last longer with the same amount of energy it is given. It is much like how a more fuel efficient car will be able to go farther on the same tank of gas, but if you pair it with a car that doesn't have as great of an mpg, when they go the same distance, the car with the greater mpg spends less fuel.
If you don't have to use the energy when you aren't utilizing it, then you can conserve the energy for when you do need it.
<u>Answer:</u> The freezing point of solution is -0.454°C
<u>Explanation:</u>
Depression in freezing point is defined as the difference in the freezing point of pure solution and freezing point of solution.
The equation used to calculate depression in freezing point follows:

To calculate the depression in freezing point, we use the equation:

Or,

where,
Freezing point of pure solution = 0°C
i = Vant hoff factor = 2
= molal freezing point elevation constant = 1.86°C/m
= Given mass of solute (KCl) = 5.0 g
= Molar mass of solute (KCl) = 74.55 g/mol
= Mass of solvent (water) = 550.0 g
Putting values in above equation, we get:

Hence, the freezing point of solution is -0.454°C
(0.48 gram) x (1mole / 4.0 gram) = 0.48/4.0 = 0.12 mole
The answer for the following questions is explained below.
Explanation:
The two variables that affect kinetic energy are:
- mass and
- velocity
- velocity - The faster an object moves,the more the kinetic energy it has.
- mass - Kinetic energy increases as mass increases
The kinetic energy of an object depends on both its mass and its velocity
Kinetic energy increases as mass increases
For example,think about rolling a bowling ball and a golf ball down a bowling lane at same velocity
Here,the bowling ball has more mass than the golf ball
Therefore you use more energy to roll the bowling ball than to roll the golf ball
The bowling ball is more likely to knock down the pins because it has more kinetic energy than the golf ball
The nails can puncture the tires of the vehicles making them deflated after a while. The process of tire deflation due to a puncture is due to the process called an effusion. Thus, option c is correct.
<h3>What is effusion?</h3>
Effusion is the process that defines the escape of the fluids or gases from a system through an outlet with a small diameter compared to the mean free path of the molecules.
When a tire is punctured then the gas from the tire starts to move out through the hole through effusion. This leads to deflation of the tire after some time as all the gas present inside had moved out completely.
Therefore, option c. a punctured tire deflates due to effusion.
Learn more about effusion here:
brainly.com/question/2823560
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