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Fantom [35]
2 years ago
14

Which of the following values for x are solutions of the equation:

Mathematics
1 answer:
andrey2020 [161]2 years ago
6 0

Answer: it’s b

Step-by-step explanation: i took the test

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kipiarov [429]
Someone help her and show how you got your answer in steps
3 0
3 years ago
Need help finding the one complete period of a non transformed contangent function
Elza [17]

One complete period of a non-transformed cotangent function is π.

The period of the function is defined as the interval after which the function value repeats itself.

For example, f(T+x)=f(x)

where T is the period of the function.

Here given that there is a non-transformed function cotangent function.

We have to find the period of the function in which interval the value of the function will repeat.

So for the function y=f(x)=cot x

the period of the function is π. means after π the value of the cotangent repeats.

cot(π+x)=cot x

Then one cycle of the cotangent graph lies between 0 and π.

Therefore One complete period of a non-transformed cotangent function is π.

Learn more about period of the function

here: brainly.com/question/3511043

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6 0
1 year ago
Slope and y intercept of 6x=4y-8 with work shown please
djverab [1.8K]

6x = 4y - 8

4y = 6x + 8

y = (3/2) x + 2

Answer: Slope 3/2, y intercept 2

6 0
2 years ago
Read 2 more answers
—7times(—8) help plz
BabaBlast [244]

Answer:

56

Step-by-step explanation:

A negative times a negative makes a positive, so:

-7*(-8)=56

8 0
2 years ago
Read 2 more answers
AB, CD, and EF intersect at O. If CD is perpendicular to EF and m
REY [17]

Answer:

m(∠AOF) = 148°

Step-by-step explanation:

From the figure attached,

CD intersects line EF at a point O.

Line CD is perpendicular to the line EF.

m(∠AOE) = 32°

m(∠COE) = 90°

Since m(∠COE) = m(∠AOE) + m(∠AOC) = 90°

32° + m(∠AOC) = 90°

m(∠AOC) = 90° - 32° = 58°

m(∠AOF) = m(∠AOC) + m(∠COF)

               = 58° + 90°

               = 148°

Therefore, m(∠AOF) = 148° will be the answer.

4 0
3 years ago
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