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Black_prince [1.1K]
3 years ago
7

Point A, B and C are colinear, and B lies between A and C. If AC= 48, AB= 2x+2 and BC= 3x+6, what is BC?

Mathematics
1 answer:
Degger [83]3 years ago
6 0
First, u have to find x so u set up this equation:
2x+2+3x+6=48
Then solve to get:
5x+8 = 48
5x=40
X=8


Then, u substitute 8 in the expression 3x+6:
3(8) +6
Ur final answer is 30.
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Given a function <img src="https://tex.z-dn.net/?f=f%28x%29%3D3x%5E4-5x%5E2%2B2x-3" id="TexFormula1" title="f(x)=3x^4-5x^2+2x-3"
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\huge\boxed{f(-1) = -7}

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<u><em>WAIT</em></u><em>!</em><em> How is this possible? </em>-1^4 = -1 (according to my calculator), and 3 \cdot -1 = -3, not 3!

It's important to note that taking a power of a negative number and multiplying a negative number are two different things. Let's use -2^2 as an example.

What your calculator did was follow BEMDAS since it wasn't explicitly told not to.

BEMDAS:

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Examining the equation, your calculator used this rule properly. Note that exponents come over multiplication.

So rather than  being <em>"-2 squared"</em> - it's <em>"the negative of of 2 squared."</em>

Tying this back into our problem, the squared method would only be true if it looks like -1^4. However, since we're substituting in -1, it looks like (-1)^4, so the expression reads out as "<u><em>-1 to the fourth.</em></u>"

MULTIPLYING -1 by itself 4 times results in -1\cdot-1\cdot-1\cdot-1=1.

Applying this logic to our original term, 3(-1)^4:

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Therefore, our first term is 3.

Let's move on to our second and third terms.

Second term: -5x^2

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Applying the same logic from our first term:

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Combining our terms, we have 3-5-2-3.

This comes out to be -7, hence, the value of f(-1) for our function f(x)=3x^4-5x^2+2x-3 is <u>-7</u>.

Hope this helped!

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