All categories

2 years ago

What will happen when a light bulb is removed from the circuit below

Physics

1 answer:

Nataliya [291]2 years ago

6 0

Answer:

C. The brightness of the remaining light bulbs will not change

Explanation:

If the battery is assumed ideal, the voltage supplied to each of the remaining two bulbs is still 9 volts. This will drive the same current through the fixed resistance of each bulb both before and after the third bulb is removed.

You might be interested in

Why does a skier wear polarized glasses instead of glasses that are used for reading?

Afina-wow [57]

<span>A skier wears polarized glasses instead of glasses that are used for reading because p</span><span>olarized glasses decrease reflected glare compared to regular glasses. (D)

Hope this answers your question correctly.</span>

8 0

2 years ago

Read 2 more answers

Mangrove forests play an important role in _______.

AysviL [449]

D. All of the above

At high tide fish will feed among the mangrove roots - rich fishing ground

The trees trap sediment and soil in the river that would flow out to sea which also helps stop erosion

Wildlife utilise almost every part of the tree, with insects and birds, monkeys and lizards in the branches, shrimps and fish in the roots, and snails and clams in the soil

4 0

1 year ago

n electromagnetic wave in vacuum has an electric field amplitude of 611 V/m. Calculate the amplitude of the corresponding magnet

enot [183]

Answer:

The corresponding magnetic field is

Explanation:

From the question we are told that

The electric field amplitude is $E_o = 611\ V/m$

Generally the magnetic field amplitude is mathematically represented as

$B_o = \frac{E_o }{c }$

Where c is the speed of light with a constant value

$c = 3.0 *0^{8} \ m/s$

$B_o = \frac{611 }{3.0*10^{8}}$

$B_o = 2.0 4 *10^{-6} \ Vm^{-2} s$

Since 1 T is equivalent to $V m^{-2} \cdot s$

$B_o = 2.0 4 *10^{-6} \ T$

6 0

3 years ago

Write SHORT examples of Gravitational potential energy and Elastic energy

Nikolay [14]

Dropping a bouncy ball and stretching a rubber ban.

6 0

2 years ago

Read 2 more answers

A train, traveling at a constant speed of 22.0 m/s, comes to an incline with a constant slope. While going up the incline, the t

Charra [1.4K]

Answer:

123.30 m

Explanation:

Given

Speed, u = 22 m/s

acceleration, a = 1.40 m/s²

time, t = 7.30 s

From equation of motion,

v = u + at

where,

v is the final velocity

u is the initial velocity

a is the acceleration

t is time

V = at + U

using equation v - u = at to get line equation for the graph of the motion of the train on the incline plane

$V_{x} = mt + V_{o}$ where m is the slope

Comparing equation (1) and (2)

$V = V_{x}$

a = m

$U = V_{o}$

Since the train slows down with a constant acceleration of magnitude 1.40 m/s² when going up the incline plane. This implies the train is decelerating. Therefore, the train is experiencing negative acceleration.

a = - 1.40 m/s²

Sunstituting a = - 1.40 m/s² and u = 22 m/s

$V_{x} = -1.40t + 22$