To develop this problem, it is necessary to apply the concepts related to Beat
The Beat is an acoustic phenomenon that is generated by two sine waves interfering with slightly different frequencies. The beat frequency is equal to the difference in the frequencies of the two original waves:
![f_{bat} = |(f_1 \pm f_B)|](https://tex.z-dn.net/?f=f_%7Bbat%7D%20%3D%20%7C%28f_1%20%5Cpm%20f_B%29%7C)
Our values are given as
![f_1 = 440Hz](https://tex.z-dn.net/?f=f_1%20%3D%20440Hz)
![f_B = 2.1Hz](https://tex.z-dn.net/?f=f_B%20%3D%202.1Hz)
For the particular case we have two possible frequencies:
![1) f_{bat} = |(f_1 - f_B)|](https://tex.z-dn.net/?f=1%29%20f_%7Bbat%7D%20%3D%20%7C%28f_1%20-%20f_B%29%7C)
![f_{bat} = |(440 - 2.1)|](https://tex.z-dn.net/?f=f_%7Bbat%7D%20%3D%20%7C%28440%20-%202.1%29%7C)
![f_{bat} = 437.9Hz](https://tex.z-dn.net/?f=f_%7Bbat%7D%20%3D%20437.9Hz)
![2) f_{bat} = |(f_B + f_1)|](https://tex.z-dn.net/?f=2%29%20f_%7Bbat%7D%20%3D%20%7C%28f_B%20%2B%20f_1%29%7C)
![f_{bat} = |(440 +2.1)|](https://tex.z-dn.net/?f=f_%7Bbat%7D%20%3D%20%7C%28440%20%2B2.1%29%7C)
![f_{bat} = 442.1Hz](https://tex.z-dn.net/?f=f_%7Bbat%7D%20%3D%20442.1Hz)
Therefore the two possibles frequencies of the other players note are 437.9Hz and 442.1Hz
Static frictional force = ƒs = (Cs) • (Fɴ)
2.26 = (Cs) • m • g
2.26 = (Cs) • (1.85) • (9.8)
Cs = 0.125
kinetic frictional force = ƒκ = (Cκ) • (Fɴ)
1.49 = (Cκ) • m • g
1.49 = (Cκ) • (1.85) • (9.8)
Cκ = 0.0822
300 miles / 6 hours = 50 miles per hour
Answer:
1.01 × 1013 picometres
Explanation:
multiply the length value by 1e+9