We can solve the problem by using Newton's second law of motion:
(1)
where
the term on the left is the resultant of the forces acting on an object
m is the mass of the object
a is the acceleration of the object
The mass of the ball in this problem is m=1 kg. Two forces are applied, in opposite directions, of 20 N and 12 N, therefore the resultant of the forces is
Therefore, we can rearrange eq.(1) and use these data to find the acceleration of the ball:
Explanation:
P.E=MGH
(1) P.E=5×10(G)×3
= 150 kg m^/s^ ( ^ =sqaure)
(2) P.E=5×10×6
= 300 kg m^/s^
Hope it helps, just remember the formula u can solve any question regarding gravition of earth (P.E=Mgh)
Fc=mv^2/r so we get
2000kg*(25m/s)^2/(80m)= 15625N of force
hope this helps! Thank You!!
Answer:
The maximum speed of sonic at the bottom of the hill is equal to 19.85m/s and the spring constant of the spring is equal to (497.4xmass of sonic) N/m
Energy approach has been used to sole the problem.
The points of interest for the analysis of the problem are point 1 the top of the hill and point 2 the bottom of the hill just before hitting the spring
The maximum velocity of sonic is independent of the his mass or the geometry. It is only depends on the vertical distance involved
Explanation:
The step by step solution to the problem can be found in the attachment below. The principle of energy conservation has been applied to solve the problem. This means that if energy disappears in one form it will appear in another.
As in this problem, the potential and kinetic energy at the top of the hill were converted to only kinetic energy at the bottom of the hill. This kinetic energy too got converted into elastic potential energy .
x = compression of the spring = 0.89