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3 years ago

I need the answer please will mark brainliest

Mathematics

2 answers:

Flura [38]3 years ago

7 0

Answer:

Look below.

Step-by-step explanation:

For further reference I suggest looking at Khan academy videos of this.

A. log8 5/9

B. log9 4

C. log6 2^3

emmasim [6.3K]3 years ago

5 0

These are the answers I have

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

Carole's car averages 13.2 mi/gal in city driving and 25.3 mi/gal in highway driving. If she drove a total of 396.0 mi on 19 gal

nika2105 [10]

Answer:

7 gallons were used for city driving.

Step-by-step explanation:

I am going to solve this question by a system of equations.

I am going to say that:

x is the number of gallons driven in the city.

y is the number of gallons driven in the highway.

19 gal of gas

This means that $x + y = 19$

Carole's car averages 13.2 mi/gal in city driving and 25.3 mi/gal in highway driving. If she drove a total of 396.0 mi.

This means that $13.2x + 25.3y = 396$

How many of the gallons (to the nearest gallon) were used for city driving?

This is x

From the first equation, i will have

$y = 19 - x$

Replacing in the second equation

$13.2x + 25.3y = 396$

$13.2x + 25.3(19 - x) = 396$

$13.2x - 25.3x = 396 - 480,7$

$12.1x = 84.7$

$x = \frac{84.7}{12.1}$

$x = 7$

7 gallons were used for city driving.

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2 years ago

Somebody please help me!!!

goldfiish [28.3K]

Answer:

Step-by-step explanation:

(2,4)

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2 years ago

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