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mamaluj [8]
3 years ago
8

Convert 66.8g to mg ! Thank you

Chemistry
1 answer:
igor_vitrenko [27]3 years ago
8 0
66.8g to mg is 66800 hope this helps

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When 10 grams of copper and 10 grams of iodine are mixed, what is the
PtichkaEL [24]
<h2>Answer:</h2>

<em>Third option is correct, 7.5 grams of CuI.</em>

<h3>Explanation:</h3>

Given data :

Mass of copper = 10 grams

Mass of iodine = 10 grams

theoretical yield of copper iodide = ?

Solution:

Moles of Cu: 10 / 63.5 = 0.157 mol.

Moles of I2: 10 / 254 = 0.039 mol.

Equation : 2Cu + I2 → 2CuI

Limiting reactant : I2

So Moles of CuI produced =  0.039 mol.

Mass of CuI = 0.039 mol * 190.5 = around 7.5g

5 0
3 years ago
If you had excess chlorine, how many moles of of aluminum chloride could be produced from 25.0 g of aluminum? Express your answe
m_a_m_a [10]

Answer:

A. From 25,0 g of aluminium you will produce 0,927 moles of aluminium chloride

B. From 30,0 g of chlorine gas you will produce: 0,282 moles of aluminium chloride

Explanation:

a. The reaction that you have in this problem is:

3 Cl₂ + 2 Al → 2 AlCl₃

25,0 g of aluminium are:

25,0 ₓ\frac{1mole}{26,98g} = 0,927 moles

As Al:AlCl₃ ratio is 1, from 25,0 g of aluminium you will produce: <em>0,927 moles of aluminium chloride</em>

b. 30,0 g of chlorine gas are:

30,0 ₓ\frac{1mole}{70,90g} = 0,423 moles of Cl₂

As Cl₂:AlCl₃ ratio is ³/₂:

0,423 moles of Cl₂ ₓ \frac{2 molesAlCl_3}{3 molesCl_2} = <em>0,282 moles of aluminium chloride</em>

Thus, from 30,0 g of chlorine gas you will produce: <em>0,282 moles of aluminium chloride</em>

<em></em>

I hope it helps!

5 0
4 years ago
How many electrons would the element calcium need to be electrically neutral? 21 11 20 40
trapecia [35]
Ca №20

N(e)=20
_______________________
4 0
3 years ago
Read 2 more answers
If 152 grams of ethane (c2h6) are reacted with 231 grams of oxygen gas, what is the mass of the excess reactant leftover after t
Naya [18.7K]
Answer is: <span>the mass of the excess reactant (ethane) leftover is 90.135 grams.
</span>Chemical reaction: 2C₂H₆(g) + 7O₂(g) → 4CO₂(g) + 6H₂O<span>(g).
m(</span>C₂H₆) = 152 g.
n(C₂H₆) = m(C₂H₆) ÷ M(C₂H₆).
n(C₂H₆) = 152 g ÷ 30 g/mol.
n(C₂H₆) = 5.067 mol.
m(O₂) = 231 g.
n(O₂) = 231 g ÷ 32 g/mol.
n(O₂) = 7.218 mol; limiting reactant.
From chemical reaction: n(O₂) : n(C₂H₆) = 7 : 2.
n(C₂H₆) = 2 · 7.218 mol ÷ 7.
n(C₂H₆) = 2.0625mol.
Δn(C₂H₆) = 5.067 mol - 2.0625 mol.
Δn(C₂H₆) = 3.0045 mol.
Δm(C₂H₆) = 3.0045 mol · 30 g/mol = 90.135 g.
6 0
4 years ago
Read 2 more answers
How many liters of space will 0.890 coles of Co2 occupy at STP
jonny [76]

Answer: 7.3 liters

Explanation:

8 0
4 years ago
Read 2 more answers
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