Mass of Na2SO4= 514.18 grams
<h3>Further explanation</h3>
Given
423.67 g of NaCl
Required
mass of Na2SO4
Solution
Reaction
2NaCl + H2SO4 → Na2SO4 + 2HCl
mol NaCl :
= 423.67 g : 58.5 g/mol
= 7.24
From the equation, mol Na2SO4 :
= 1/2 x mol NaCl
= 1/2 x 7.24
= 3.62
Mass Na2SO4 :
= 3.62 mol x 142,04 g/mol
= 514.18 grams
Just 7 electrons this is the answer
Answer:
P = 0.0373 atm
Explanation:
Given data:
Mass of krypton = 1.86 g
Volume of krypton = 17.5 L
Temperature of krypton = 190 F
Pressure of krypton = ?
Solution:
First of all we will calculate the number of moles.
Number of moles = mass/ molar mass
Number of moles = 1.86 g/ 83.9 g/mol
Number of moles = 0.022 mol
Formula:
PV = nRT
P = nRT / V
P = 0.022 mol × 0.0821 atm. L. mol⁻¹. K⁻¹ × 360.928 K / 17.5 L
P = 0.652 atm. L /17.5 L
P = 0.0373 atm
Explanation:
At the end of mitosis, the new daughter cells contain the same number of chromosomes as the parent cell. Mitosis enables cellular growth and repair in multicellular organisms.
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