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Lera25 [3.4K]
3 years ago
8

Which property describes the shininess of an element?

Chemistry
2 answers:
Vinil7 [7]3 years ago
7 0

Answer:

Metals are shiny and lustrous with a high density.

They have very high melting and boiling points because metallic bonding is very strong, so the atoms are reluctant to break apart into a liquid or gas.

goldenfox [79]3 years ago
6 0

Answer: Metals are shiny and lustrous with a high density. They have very high melting and boiling points because metallic bonding is very strong, so the atoms are reluctant to break apart into a liquid or gas.

Explanation:

sorry for not answering in less than 1 minute

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What’s the distance from the nucleus of an atom to its theoretical outer edge of electron orbits
ollegr [7]

Answer:

The range of atoms = (30-300 pm) depending upon the element

Explanation:

The Atomic radii of the atom is the distance from the center of the circle to the outermost orbital.

The center of the circle is the nucleus and the radii is the outermost boundary.

The actual size of the atom is decided on the basis of the Zeff . Also known as <em>effective nuclear charge.</em>

<em>Zeff: It is the net positive charge felt by the outermost electron by the nucleus.</em>

<em>The value of Zeff depends upon the shielding constant. More the shielding less will be the Zeff . Hence the size of the atom increases.</em>

Due to shielding the outermost electrons feel less pull of nucleus.

<em>The greater the Zeff , the smaller the radius of the atom.</em>

The formula used to calculate the atomic mass is :

r_{n}=\frac{52.9n^{2}}{Z}pm

Here "pm"= picometers

1 pm = 10^{-12}m

<u>The size of the smallest atom H-atom = 120 pm</u>

<u>The range of atoms = (30-300 pm)</u>

4 0
3 years ago
All of the following conditions of STP are true except A. 101.3 kPa B. 273.15 K C. 22.4 L D. 3.81 kPa
kaheart [24]
  3.81   kpa  is  the  condition   which  is  not  true   at  STP

According  to  IUPAC  the  standard  temperature  and  pressure  that  is  STP  the  temperature  is   273.15  k  or  0   degrees  celsius .  and  the  absolute  temperature   of   101.325 Kpa   or  1  atm.  In  addition at STP   the  volume of  ideal  gas  is  22.4 
8 0
3 years ago
Write the chemical equation for fot the reaction between mgcl2 and the soap you preapred
In-s [12.5K]
Soap is the sodium or potassium salt of long chain of fatty acid. Fatty acids when treated with NaOH or KOH forms Soap. This process is called as Saponification. Examples of Soap are as follow,

                                     1.  Sodium Stearate C₁₇H₃₅COONa
                                   
                                     2.  Potassium Oleate C₁₇H₃₃COOK

Reaction of Soap with MgCl₂;

When Soap is treated with MgCl₂ or CaCl₂ it forms insoluble precipitate called S.C.U.M. The reactions with MgCl₂ are as follow,

                2C₁₇H₃₅COONa + MgCl₂  -------->  2C₁₇H₃₅COOMg  + 2 NaCl

                2C₁₇H₃₃COOK   + MgCl₂  -------->  2C₁₇H₃₅COOMg  + 2 KCl

These reaction are often found in hard water. And this reaction decreases the effectiveness of soap.
5 0
3 years ago
A sample of the amino acid tyrosine is barely soluble in water. Would a peptide containing only a string of Tyr residues be more
Misha Larkins [42]

Answer:

Tyrosine is a polar and aromatic compound. its side chain acidity and basicity is neutral

if a peptide contain only a string of tyrosine residue especially l tyrosine the solubility increases more

Explanation:

even tyrosine number remains constant, tyrosine containing peptide will be more soluble. This peptide is soluble in 1 M HCl (100 mg/ml), with heating. The solubility in water (25 °C) is 0.45 mg/ml in the pH range 3.2 - 7.5.

2.0 mg/ml; at pH 9.5, the solubility is 1.4 mg/ml; and at pH 10, the solubility is 3.8 mg/ml.

5 0
3 years ago
A 1.450 g sample of an unknown organic compound , X, is dissolved in 15.0 g of toluene
muminat

Answer:

Molecular weight of the compound = 372.13 g/mol

Explanation:

Depression in freezing point is related with molality of the solution as:

\Delta T_f = K_f \times m

Where,

\Delta T_f = Depression in freezing point

K_f = Molal depression constant

m = Molality

\Delta T_f = K_f \times m

1.33 = 5.12 \times m

m = 0.26

Molality = \frac{Moles\ of\ solute}{Mass\ of\ solvent\ in\ kg}

Mass of solvent (toluene) = 15.0 g = 0.015 kg

0.26 = \frac{Mole\ of\ compound}{0.015}

Moles of compound = 0.015 × 0.26 = 0.00389 mol

Mol = \frac{Mass\ in\ g}{Molecular\ weight}

Mass of the compound = 1.450 g

Molecular\ weight = \frac{Mass\ in\ g}{Moles}

Molecular weight = \frac{1.450}{0.00389} = 372.13\ g/mol

4 0
3 years ago
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